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(-4^2)(2^-1)
Question|Asked by Jonah Allen
Asked 6/6/2015 1:54:33 PM
Updated 6/6/2015 7:31:24 PM
1 Answer/Comment
Flagged by alfred123 [6/6/2015 7:31:23 PM]
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User: (-4^2)(2^-1)

Question|Asked by Jonah Allen
Asked 6/6/2015 1:54:33 PM
Updated 6/6/2015 7:31:24 PM
1 Answer/Comment
Flagged by alfred123 [6/6/2015 7:31:23 PM]
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8
(-4^2)(2^-1)

= (-16)(1/2);

= -16/2;

= -8
Added 6/6/2015 7:31:24 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [6/6/2015 7:42:03 PM]
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Questions asked by Jonah Allen
(y^4-1)/(y+1)
Question|Asked by Jonah Allen
Not Answered
Updated 6/6/2015 2:33:11 PM
1 Answer/Comment
(y^4-1)/(y+1)
= (y^4/y+1) - (1/y+1)
= y^3 - y^2 + y - 1 (for y is not equal to -1).
Added 6/6/2015 2:33:11 PM
This answer has been confirmed as correct and helpful.
(3/a^2b)+(2/ab^2)
Question|Asked by Jonah Allen
Updated 6/7/2015 9:22:04 AM
1 Answer/Comment
(3/a^2b)+(2/ab^2)
= 2a^2b + 3ab^2 / a^3b^3
=2a + 3b / a^2b^2

Added 6/7/2015 9:21:56 AM
This answer has been confirmed as correct and helpful.
4x^3y(-2x^2y)
Weegy: 4x^3y*(-2x^2y) = -8x^5y^2 User: x^1=? (More)
Question|Asked by Jonah Allen
Updated 6/7/2015 9:16:02 AM
1 Answer/Comment
x^1 = x
Added 6/7/2015 9:16:02 AM
This answer has been confirmed as correct and helpful.
(5x 2 + 2x - 3)(x - 1)
Weegy: (5x^2 + 2x - 3)(x - 1) = 5x^3 + 2x^2 - 3x - 5x^2 - 2x + 3 = 5x^3 - 3x^2 - 5x + 3 User: (8/r^3s^2)/(6/rs^4) (More)
Question|Asked by Jonah Allen
Updated 6/7/2015 9:20:34 AM
1 Answer/Comment
(8/r^3s^2)/(6/rs^4)
= 8rs^4/6r3s^2
= 8s^2/6r^2
= 4s^2/3r^2

Added 6/7/2015 9:20:34 AM
This answer has been confirmed as correct and helpful.
d+3/8d-2d+1/10d^2
Question|Asked by Jonah Allen
Updated 6/7/2015 9:24:12 AM
1 Answer/Comment
[(d+3)/(8d-2d)]+[1/(10d^2)]
= 10d^3 + 30d^2 + 6d/ 60d^3
= 10d^2 + 30d + 6 / 60d^2
= 5d^2 + 15d + 3 / 30d^2


Added 6/7/2015 9:24:12 AM
This answer has been confirmed as correct and helpful.
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