Question and answer
X^2+5X+6
Question
Asked 11/29/2014 9:34:29 PM
Updated 12/2/2014 10:45:16 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yumdrea [12/2/2014 10:45:16 PM]
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Original conversation
User: X^2+5X+6

Weegy: x^3(x^2 + 5x + 1)

(x^3)(x^2 + 5x + 1)

(x^3)(x^2)+(x^3)(5x)+(x^3)(1)

x^5 + 5x^4 + x^3


User: x^2+5x+6

User: Explain how to factor the following trinomials forms: x2 + bx + c and ax2 + bx + c. Is there more than one way to factor this? Show your answer using both words and mathematical notation.

Weegy: Let's factor the trinomial x? + bx + c. We know that if b?-4c >= 0 then this trinomial has zeros and it can be factorized. [ It's zeros are x1 = [ -b + ?(b?-4c) ] / 2 and x2 = [ -b - ?(b?-4c) ] / 2. So, we can factor it as x? + bx + c = (x-x1)(x-x2). In a case of trinomial ax? + bx + c we can factorize it as ax? + bx + c = a(x? + b/a?x + c/a), where the trinomial x? + b/a?x + c/a has the same form as x? + bx + c. ]
emdjay23|Points 18763|

Question
Asked 11/29/2014 9:34:29 PM
Updated 12/2/2014 10:45:16 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yumdrea [12/2/2014 10:45:16 PM]
New answers
Rating
5
x^2 + 5x + 6
= x*x + 2x + 3x + 2*3
= (x + 2)(x + 3)
Added 12/1/2014 10:32:30 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [12/2/2014 10:45:18 PM]
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