If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
A. 0.002010812 m3
B. 0.004021624 m3
C. 0.002021624 m3
D. 0.000010812 m3

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20 C, the volume at 50 C will be 0.002010812 m3. Solution: V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.

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Asked 2/1/2019 7:25:18 AM

Updated 11/14/2020 8:00:53 PM

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If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20 C, the volume at 50 C will be 0.002010812 m3.

Solution: V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.

Solution: V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.

Added 11/14/2020 8:00:53 PM

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If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?

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Not Answered

Updated 11/14/2020 8:11:17 PM

1 Answer/Comment

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20 C, the volume at 50 C will be 0.002010812 m3.

V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.

V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.

Added 11/14/2020 8:11:17 PM

This answer has been confirmed as correct and helpful.

A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to expand to 6.5 m3, its new temperature is 277 K. What's the absolute pressure of the gas after expansion?

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Updated 11/26/2021 5:53:50 PM

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A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to expand to 6.5 m3, its new temperature is 277 K. the absolute pressure of the gas after expansion is 279.2 KPa. P1V1/T1 =P2V2/T2 , 475 *4 /290 = 6.5 *P2 /277 , P2 = 475 *4 *277 /290 *6.5 = 526300 / 1885 = 279.2 KPa

Added 11/26/2021 5:53:50 PM

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How much energy, in joules, is released when 17 kilograms of granite is cooled from 45°C to 21°C?

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Updated 11/27/2021 4:18:15 PM

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327,992.8 J is released when 17 kilograms of granite is cooled from 45 C to 21 C.

Solution: U = mCp(Tf-Ti); U = 17 kg (790 J/(kg-°C)) (21-45) = 322,320 Joules or 327,992.8 J.

Solution: U = mCp(Tf-Ti); U = 17 kg (790 J/(kg-°C)) (21-45) = 322,320 Joules or 327,992.8 J.

Added 11/27/2021 4:18:15 PM

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How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?

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Updated 12/19/2021 4:12:53 PM

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697.08 J of energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature. Latent heat = m (deltaH) , 0.06 *11.6 = 0.697 KJ = 697.08 J

Added 12/19/2021 4:12:53 PM

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How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?

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Updated 322 days ago|3/11/2022 8:40:10 AM

1 Answer/Comment

697.08 J of energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature. Latent heat = m (deltaH) , 0.06 *11.6 = 0.697 KJ = 697.08 J

Added 322 days ago|3/11/2022 8:40:10 AM

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