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If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C? A. 0.002010812 m3 B. 0.004021624 m3 C. 0.002021624 m3 D. 0.000010812 m3
If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20 C, the volume at 50 C will be 0.002010812 m3. Solution: V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.
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Asked 2/1/2019 7:25:18 AM
Updated 11/14/2020 8:00:53 PM
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If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20 C, the volume at 50 C will be 0.002010812 m3.

Solution: V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.
Added 11/14/2020 8:00:53 PM
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If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
Question
Not Answered
Updated 11/14/2020 8:11:17 PM
1 Answer/Comment
If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20 C, the volume at 50 C will be 0.002010812 m3.

V =V [1 + (50-30)] = 0.002 [1 + 0.00018(30)] = 0.0020108 m³.
Added 11/14/2020 8:11:17 PM
This answer has been confirmed as correct and helpful.
A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to expand to 6.5 m3, its new temperature is 277 K. What's the absolute pressure of the gas after expansion?
Question
Not Answered
Updated 11/26/2021 5:53:50 PM
1 Answer/Comment
A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to expand to 6.5 m3, its new temperature is 277 K. the absolute pressure of the gas after expansion is 279.2 KPa. P1V1/T1 =P2V2/T2 , 475 *4 /290 = 6.5 *P2 /277 , P2 = 475 *4 *277 /290 *6.5 = 526300 / 1885 = 279.2 KPa
Added 11/26/2021 5:53:50 PM
This answer has been confirmed as correct and helpful.
How much energy, in joules, is released when 17 kilograms of granite is cooled from 45°C to 21°C?
Question
Not Answered
Updated 11/27/2021 4:18:15 PM
1 Answer/Comment
327,992.8 J is released when 17 kilograms of granite is cooled from 45 C to 21 C.

Solution: U = mCp(Tf-Ti); U = 17 kg (790 J/(kg-°C)) (21-45) = 322,320 Joules or 327,992.8 J.
Added 11/27/2021 4:18:15 PM
This answer has been confirmed as correct and helpful.
How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?
Question
Not Answered
Updated 12/19/2021 4:12:53 PM
1 Answer/Comment
697.08 J of energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature. Latent heat = m (deltaH) , 0.06 *11.6 = 0.697 KJ = 697.08 J
Added 12/19/2021 4:12:53 PM
This answer has been confirmed as correct and helpful.
How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?
Question
Not Answered
Updated 322 days ago|3/11/2022 8:40:10 AM
1 Answer/Comment
697.08 J of energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature. Latent heat = m (deltaH) , 0.06 *11.6 = 0.697 KJ = 697.08 J
Added 322 days ago|3/11/2022 8:40:10 AM
This answer has been confirmed as correct and helpful.
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