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What is the equation of the line that passes through the points (–2, 2) and (0, 5)? A. y = 3/2x + 5 B. y = x – 5 C. y = –3/2x + 5 D. y = x + 5
Slope , m = y2-y1 /x2-x1 = 5-2/0-(-2) = 3/2; Equation of line, y = mx +c, substitute value (0,5) in equation, 5 = 0(3/2) + c , c =5, y = mx +c , substitute value of m and c , y = 3/2*x + 5, y =3/2 x +5
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Asked 3/28/2018 1:27:26 PM
Updated 3/28/2018 11:41:45 PM
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Slope , m = y2-y1 /x2-x1 = 5-2/0-(-2) = 3/2; Equation of line, y = mx +c, substitute value (0,5) in equation, 5 = 0(3/2) + c , c =5, y = mx +c , substitute value of m and c , y = 3/2*x + 5, y =3/2 x +5
Added 3/28/2018 11:41:45 PM
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Questions asked by the same visitor
A series circuit contains a generator, two devices, and connecting wires. The resistances of the two devices are 15 ohms and 10 ohms. The voltage supplied by the generator is 75 V. What will be the voltage drop in the device with 10 ohms of resistance? A. 3 V B. 25 V C. 30 V D. 45 V
Question
Updated 9/16/2019 11:45:22 PM
1 Answer/Comment
A series circuit contains a generator, two devices, and connecting wires. The resistances of the two devices are 15 ohms and 10 ohms. The voltage supplied by the generator is 75 V. The voltage drop in the device with 10 ohms of resistance will be 30 V.

Solution:
Voltage drop=Voltage * Resistor / total resistance
e = 75 * 10/25
e = 3 * 10
e = 30 V
Added 9/16/2019 11:45:22 PM
This answer has been confirmed as correct and helpful.
Combining which of the following substances with germanium will cause the germanium to emit free electrons? A. Indium B. Aluminum C. Bismuth D. Gallium
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Updated 9/16/2019 11:50:05 PM
1 Answer/Comment
Combining Gallium with germanium will cause the germanium to emit free electrons.
Added 9/16/2019 11:50:05 PM
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Which of the following usually occurs with a short circuit? A. All parts of the circuit will begin to carry higher amounts of current than normal. B. Most of the current will flow through one part of the circuit. C. The material within a fuse may begin to melt when the current ceases to exist. D. All parts of the circuit will begin to carry lower amounts of current than normal.
Question
Updated 229 days ago|4/9/2020 6:46:19 PM
1 Answer/Comment
All parts of the circuit will begin to carry higher amounts of current than normal. -usually occurs with a short circuit.
Added 229 days ago|4/9/2020 6:46:19 PM
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