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The Big Bang Theory is supported by: triangulation red shift data parallax angles heliocentric theory
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Asked 5/5/2014 12:01:04 PM
Updated 5/5/2014 12:18:23 PM
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Flagged by alfred123 [5/5/2014 12:18:21 PM]
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User: The Big Bang Theory is supported by: triangulation red shift data parallax angles heliocentric theory

Weegy: The answer is A. triangulation
Butterflybaby|Points 1128|

Question
Asked 5/5/2014 12:01:04 PM
Updated 5/5/2014 12:18:23 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by alfred123 [5/5/2014 12:18:21 PM]
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The Big Bang Theory is supported by: RED SHIFT DATA.
Added 5/5/2014 12:18:23 PM
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Questions asked by the same visitor
A what is a verb form ending in -ing and used as a noun?
Weegy: A verb form ending in -ing and used as a noun is a Gerund. (More)
Question
Updated 12/8/2018 11:08:08 AM
0 Answers/Comments
Apparent magnitude: is the same as absolute magnitude is always brighter than the absolute magnitude represents how bright a star would be one A.U. from earth represents how bright a star seems when viewed from earth
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Not Answered
Updated 9/24/2017 12:06:08 PM
1 Answer/Comment

Apparent magnitude: represents how bright a star seems when viewed from earth.

Added 9/24/2017 12:06:08 PM
This answer has been confirmed as correct and helpful.
Factor a 3 - 3 + 3a 2 - a. (a - 1)(a + 1)(a + 3) (a2 + 1)(a - 3) (a2 - 3)(a + 1)
Weegy: a^2 - a - 20, the factors are (a-5)(a+4) (More)
Question
Updated 4/30/2014 1:20:48 AM
1 Answer/Comment
a^3 - 3 + 3a^2 - a
= a^2(a + 3) - (a + 3)
= (a + 3)(a^2 - 1)
= (a + 3)(a - 1)(a + 1)
Added 4/30/2014 1:20:48 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/30/2014 1:29:46 AM]
Which of the following is the complete factorization of 25a2 - 100? 5(5a - 2)(5a + 2) (5a - 2)(5a + 2) 25(a - 2)(a + 2)
Weegy: Which of the following is the complete factorization of 25a2 - 100? (5a +10)(5a-10) [ ] (More)
Question
Updated 4/30/2014 5:32:38 AM
1 Answer/Comment
25a2 - 100 is 25 (a-2) (a+2) the complete factorization.
Added 4/30/2014 5:32:38 AM
This answer has been confirmed as correct and helpful.
Factor completely. n 4 - 1 (n2 + 1)(n - 1) (n + 1)2(n - 1)(n + 1) (n2 + 1)(n - 1)(n + 1)
Weegy: n^4 - 1 = (n^2 + 1)(n^2 - 1) = (n^2 + 1)(n - 1)(n + 1) (More)
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Updated 4/29/2014 9:29:10 PM
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