Determine current density in a copper wire of radius 1.4 mm carrying 6 A.

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Given: I = 6 A r = 1.4 mm = 0.0014 m Area A = r² A = n × (0.0014)² A = 6.16×10 m² Current density J = I / A J = 6 / 6.16×10 J = 9.74×10 A/m² Answer: 9.74×10 A/m²

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Asked 34 days ago|2/1/2026 10:33:14 AM

Updated 33 days ago|2/2/2026 5:59:10 AM

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cruz30

Given:
I = 6 A
r = 1.4 mm = 0.0014 m
Area A = r²
A = n × (0.0014)²
A = 6.16×10 m²
Current density J = I / A
J = 6 / 6.16×10
J = 9.74×10 A/m²
Answer: 9.74×10 A/m²

Added 33 days ago|2/2/2026 5:57:56 AM

This answer has been confirmed as correct and helpful.

Salas1987

J = I/A,

The radius (r) is given as 1.4 mm, which is 1.4 x 10^-3 meters.

A = r^2. A = * (1.4 x 10^-3 m)^2 = * 1.96 x 10^-6 m^2 = 6.1575 x 10^-6 m^2.

The current (I) is given as 6 A.
J = 6 A / (6.1575 x 10^-6 m^2) = 9.744 x 10^5 A/m^2.

Therefore, the current density in the copper wire is approximately 9.744 x 10^5 A/m^2.

Added 33 days ago|2/2/2026 5:59:10 AM

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Deleted by Salas1987 [2/2/2026 5:50:04 AM]

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