Find the discriminant, and determine the number of real solutions. Then solve x^2+2x+17=0

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Asked 11/20/2014 6:44:00 PM

Updated 11/25/2014 11:25:38 PM

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Flagged by yeswey [11/25/2014 11:21:18 PM]

s

= 4x^2 + 6x - 6x - 9;

= 4x^2 - 9

Question

Asked 11/20/2014 6:44:00 PM

Updated 11/25/2014 11:25:38 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by yeswey [11/25/2014 11:21:18 PM]

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8

x^2 + 2x + 17 = 0

a = 1, b = 2, c = 17

discriminant = b^2 - 4ac = 2^2 - 4(1)(17) = 4 - 68 = -64 < 0

there are No Real Solutions, there are Two Imaginary Solutions.

x = (-2 ± sqrt (-64)]/2

= (-2 ± 8i)/2

= -1 ± 4i

a = 1, b = 2, c = 17

discriminant = b^2 - 4ac = 2^2 - 4(1)(17) = 4 - 68 = -64 < 0

there are No Real Solutions, there are Two Imaginary Solutions.

x = (-2 ± sqrt (-64)]/2

= (-2 ± 8i)/2

= -1 ± 4i

Added 11/25/2014 11:25:38 PM

This answer has been confirmed as correct and helpful.

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