Solve 2x 2 + x - 6 = 0 {-2, 3/2} {-3/2, 2} {}
Question
Updated 11/15/2014 2:29:39 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [11/15/2014 2:29:39 AM]
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Original conversation
User: Solve 2x 2 + x - 6 = 0 {-2, 3/2} {-3/2, 2} {}

Weegy: -2(2x + 5) - 3 = -3(x - 1)

-4x - 10 - 3 = -3x + 3;

-4x + 3x = 3 + 10 + 3;

-x = 16;

x = -16

User: If x2 - 6x + 8 = 0, then x - 4 = 0 or x - 2 = 0. True False

User: If i is raised to an even power, then it can not simplify to be -1 1 i

Question
Updated 11/15/2014 2:29:39 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [11/15/2014 2:29:39 AM]
Rating
5
2x^2 + x - 6 = 0
(2x - 3)(x + 2) = 0
when 2x - 3 = 0,x = 3/2
when x + 2 = 0,x = -2
So the solution for 2x^2 + x - 6 = 0 is {3/2, -2}.
Confirmed by sujaysen [11/15/2014 1:05:51 PM]
5
If x2 - 6x + 8 = 0, then x - 4 = 0 or x - 2 = 0 is true .
x^2 - 6x + 8 = 0
(x - 2)(x - 4) = 0
So x - 2 =0 , x - 4 = 0 .

Questions asked by the same visitor
Find the center of the following equation. x 2 + y 2 + 8 x - 6 y - 15 = 0
Question
Updated 11/10/2014 11:24:59 PM
x^2 + y^2 + 8x - 6y - 15 = 0
(x + 4)^2 - 16 + (y - 3)^2 - 9 - 15 = 0
(x + 4)^2 + (y - 3)^2 = 40
(-4 , 3) is the center of equation.:x^2 + y^2 + 8x - 6y - 15 = 0 .
Confirmed by jeifunk [11/11/2014 12:51:23 AM]
What is the solution set of 2x(x - 1) = 3? User: Which of the following constants can be added to x2 - 10x to form a perfect square trinomial? 10 25 100 User: Write the quadratic equation in factored form. Be sure to write the entire equation. x2 + x - 12 = 0
Weegy: (x+4)(x-3)=0 User: If the quadratic formula is used to find the solution set of 3x 2 + 4x - 2 = 0, what are the solutions? User: What is the value of b2 - 4ac for the following equation? 2x2 + 3x = -1 0 1 17 Weegy: The answer is: b.1 [smile] User: What is the solution set of 7x 2 + 3x = 0? {0, 3/7} {0, -3/7} {0, -4/7} Weegy: The solution set of 7x^2 + 3x = 0 is: B. {0, -3/7}. User: What is the solution set of x 2 + 5x + 1 = 0? User: What is the solution set of (3x - 1)2 = 5? (More)
Question
Updated 11/11/2014 7:37:43 AM
(3x - 1)^2 = 5
3x - 1 = ± sqrt 5
3x = 1 ± sqrt 5
x = (1 ± sqrt 5)/3
x^2 + 5x + 1 = 0
a = 1, b = 5, c = 1
discriminant = b^2 - 4ac = 25 - 4 = 21
x = (-5 ± sqrt 21)/2
The radius of the circle whose equation is (x + 4)² + (y - 2)² = 36 is 36 18 6
Weegy: If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its radius is 6. User: The distance between the points (5, -2) and (-7, 3) is 5 29 13 (More)
Question
Updated 11/12/2014 10:56:02 PM
The distance between the points (5, -2) and (-7, 3) is 13 .
Let the distance is d
d^2 = (-7-5)^2 + {3 - (-2)}^2
d^2 = 144 + 25
d^2 = 169
d = 13
Confirmed by jeifunk [11/12/2014 10:56:22 PM], Rated good by jeifunk
Solve (x + 2)(2x + 3) = 6 {-2, -3/2} {-7/2, 0} {0}
Question
Updated 11/15/2014 2:38:32 PM
The solution set for (x + 2)(2x + 3) = 6 is {-7/2, 0}.

(x + 2)(2x + 3) = 6;
2x^2 +3x + 4x + 6 = 6;
2x^2 + 7x + 6 - 6 = 0;
2x^2 + 7x = 0;
x(2x + 7) = 0;
x = 0;
2x + 7 = 0; 2x = -7; x = -7/2
What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)? (-10.5, 5) (-10.5, 7) (-2.5, 7)
Weegy: The midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2) is (-10.5, 5). ((x1+x2)/2, (y1+y2)/2); = ((-8 - 13)/2, (12 - 2)/2) = (-21/2, 10/2) = (-10.5, 5) User: What is the length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12? 13 15 17 Weegy: The length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12 is 13. User: Find the midpoint of the line segment whose endpoints are (3, 10) and (7, 8). (2, 1) (5, 9) (11, 12) Weegy: Find the midpoint of the line segment whose endpoints are (3, 10) and (7, 8) is: (5, 9). M = [(x2 + x1)/2] , [(y2 + y1)/2]; = [(3 + 7)/2] , [(10 + 8)/2]; = (10, 2) , (18, 2); = (5, 9) User: What is the equation of a circle whose center is at the origin and whose radius is 16? x2 + y2 = 4 x2 + y2 = 16 x2 + y2 = 256 (More)
Question
Updated 11/15/2014 2:39:44 PM
The equation of a circle whose center is at the origin and whose radius is 16 is: x^2 + y^2 = 256
Confirmed by andrewpallarca [11/15/2014 2:39:54 PM]
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