Question and answer
How many moles of Ag contain 4.49 x10^23 atoms Ag? a. 0.745 x10^24 mol c. 0.745 mol b. 0.745 x10^23 mol d. 27.0 mol
1 mole = 6.02 x 10^23; the number of moles of Ag contain 4.49 x10^23 atoms Ag is: (4.49 x 10^23 )/(6.02 x 10^23)= 0.745 mol.
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Expert answered|yeswey|Points 13271|
Question|Asked by swagless
Asked 6/6/2014 7:49:20 AM
Updated 6/8/2014 12:26:46 AM
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