Polar to Cartesian: r=5, = /4

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r = 5, theta = n/4 x = r cos(theta) = 5cos(n/4) = 5*sqrt(2)/2 y = r sin(theta) = 5sin(n/4) = 5*sqrt(2)/2 (x,y) = (5*sqrt(2)/2,5*sqrt(2)/2)

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Asked 9 days ago|4/7/2026 11:51:29 AM

Updated 9 days ago|4/7/2026 12:10:06 PM

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Added 9 days ago|4/7/2026 12:09:34 PM

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cruz30

r = 5, theta = n/4
x = r cos(theta) = 5cos(n/4) = 5*sqrt(2)/2
y = r sin(theta) = 5sin(n/4) = 5*sqrt(2)/2
(x,y) = (5*sqrt(2)/2,5*sqrt(2)/2)

Added 9 days ago|4/7/2026 12:10:06 PM

This answer has been confirmed as correct and helpful.

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