Find the product. -7(-a 2)(-b 3)
Question
Updated 6/11/2014 4:53:35 AM
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Flagged by yeswey [6/11/2014 4:53:16 AM]
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Original conversation
User: Find the product. -7(-a 2)(-b 3)

Weegy: The product for -7(-a^2)(-b^3) is -7a^2b^3. The reason is obvious. We have 3 negatives and when there is an odd number of negatives, the product is negative. The variables are being squared. [ That means if the bases are the same, we can add the two exponents together. Unfortunately, the bases are not the same. The -7 cannot be matched with anything else. Therefore, the answer is -7a^2b^3. ]
Ashnicole49|Points 104|

User: Find the product. x 5 · x 4 · x 3

Question
Updated 6/11/2014 4:53:35 AM
This conversation has been flagged as incorrect.
Flagged by yeswey [6/11/2014 4:53:16 AM]
Rating
8
x^5 · x^4 · x^3 = x^12
Confirmed by jeifunk [6/11/2014 4:55:12 AM]

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