factor 10b2 +17b + 3 completely
Question
Asked 4/28/2014 11:33:12 AM
Updated 4/29/2014 3:11:07 AM
Original conversation
User: factor 10b2 +17b + 3 completely

Weegy: 10b2 +17b + 3, factors are: (2b+3)(5b+1).
andrewpallarca|Points 35847|

User: factor 5c2 +30c + 45 completely

Question
Asked 4/28/2014 11:33:12 AM
Updated 4/29/2014 3:11:07 AM
Rating
3
5c^2 +30c + 45
= 5(c^2 + 6c + 9)
= 5(c + 3)(c + 3)
= 5(c + 3)^2
Added 4/29/2014 3:11:07 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/29/2014 3:17:27 AM]

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Questions asked by the same visitor
factor 3x2 + 2xy - y2 completely
Weegy: Solution: 3x2 + 2xy - y2 = (3x - y)(x + y). User: factor 4x2+ 8xy - 60y2 completely (More)
Question
Updated 4/29/2014 3:13:25 AM
4x^2+ 8xy - 60y^2
= 4(x^2 + 2xy - 15y^2)
= 4(x - 3y)(x + 5y)
Added 4/29/2014 3:13:25 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/29/2014 3:17:23 AM]
factor 2x2 - 16x + 32 completely
Question
Updated 4/28/2014 1:18:37 PM
2x^2 - 16x + 32 = 2(x^2 - 8x + 16) = 2(x -4)^2
Added 4/28/2014 1:18:37 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [4/28/2014 1:19:28 PM]
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