What is the fractional equivalent of 0.2323...?
23/99 is the fractional equivalent of 0.2323...
smp0784|Points 4142|
Question
Updated 9/26/2014 12:10:02 PM
Edited by jeifunk [9/26/2014 12:09:39 PM], Edited by jeifunk [9/26/2014 12:10:01 PM], Confirmed by jeifunk [9/26/2014 12:10:02 PM]
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Questions asked by the same visitor
5x + 2y = 8/x + y = 4 If you want to solve the system of equations by addition, which of the following could you do? Multiply the second equation by 5 and add. Multiply the second equation by 2 and add. Multiply the second equation by -2 and add.
Question
Updated 9/22/2014 2:28:52 PM
5x + 2y = 8, x + y = 4 If you want to solve the system of equations by addition, Multiply the second equation by -2 and add.
(x + y = 4) x (-2) =
(-2x - 2y = -8) + (5x + 2y = 8) =
3x = 0; x = 0/3; x = 0;
Plug x = 0:
5(0) + 2y = 8;
2y = 8; y = 8/2; y = 4
Simplify 2(x - 3) + 7(x + 2). 9x - 8 9x + 3 9x + 8
Question
Updated 9/24/2014 9:29:03 PM
2(x - 3) + 7(x + 2) = 2x - 6 + 7x + 14 = 9x + 8
Confirmed by andrewpallarca [9/26/2014 11:43:13 AM]
Simplify 2(x - 3) + 7(x + 2). 9x - 8 9x + 3 9x + 8
Weegy: 2(x - 3) + 7(x + 2) = 2x - 6 + 7x + 14 = 9x + 8 (More)
Question
Updated 9/26/2014 11:40:13 AM
Find the value of 7 + 32 (-5 + 1) ÷ 2. 25 32 -11
Weegy: 7 + 32 (-5 + 1) ÷ 2 = 7 + 32(-4) ÷ 2 = 7 - 128 ÷ 2 = 7 - 64 = -57 (More)
Question
Updated 9/26/2014 11:42:49 AM
Find two consecutive integers whose sum is 73. Which of the following equations could be used to solve the problem?
Weegy: x + (x + 1) = 73; 2x + 1 = 73; 2x = 73 - 1; 2x = 72; x = 72/2; x = 36, the next integer is 37. 36 + 37 = 73. The equation 2x + 1 = 73 could be used to solve the problem. (More)
Question
Updated 9/26/2014 1:46:34 PM
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