A chef prepared five chocolate tortes for a dinner party. The guests consumed 2 5/16 tortes. How many tortes are left? A. 3 11/16 B. 2 9/16 C. 3 9/16 D. 2 11/16

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Asked 12/10/2015 9:19:17 AM

Updated 12/10/2015 9:50:05 AM

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This answer has been confirmed as correct and helpful.

Edited by jeifunk [12/10/2015 9:50:04 AM], Confirmed by jeifunk [12/10/2015 9:50:05 AM]

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User: A chef prepared five chocolate tortes for a dinner party. The guests consumed 2 5/16 tortes. How many tortes are left? A. 3 11/16 B. 2 9/16 C. 3 9/16 D. 2 11/16

Weegy: 2 11/16 tortes are left.

5 - (2 5/16)
= 5 - 37/16
= 43 / 16
= 2 11/16
Sting|Points 6733|

User: Reduce the fraction 36/48 to its lowest terms. A. 3/4 B. 1 12/48 C. 1 1/4 D. 6/8

Weegy: 36 / 48 = 3 / 4

User: 9/11 = /22 A. 12 B. 9 C. 4 D. 18

Weegy: 9/11 = 18/22

9/11 = x/22
(9)*(22)=x*(11)
198=11x
11x=198
x = 198/11
x = 18
Narkotiq|Points 337|

User: What is the product of 4 2/3 and 11 1/4? A. 44 2/12 B. 56/135 C. 8 3/7 D. 52 1/2

Weegy: 4 2/3 * 11 1/4
= 14/3 * 45/4;
= 630/12;
= 105/2;
= 52 1/2

User: 6. 7 1/5 – 6 2/5 = ? A. 1 4/5 B. 1 1/5 C. 13 3/5 D. 4/5

Question

Asked 12/10/2015 9:19:17 AM

Updated 12/10/2015 9:50:05 AM

1 Answer/Comment

This answer has been confirmed as correct and helpful.

Edited by jeifunk [12/10/2015 9:50:04 AM], Confirmed by jeifunk [12/10/2015 9:50:05 AM]

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jeifunk

7 1/5 - 6 2/5
= 36/5 - 32/5
= 4/5

Added 12/10/2015 9:47:08 AM

This answer has been confirmed as correct and helpful.

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