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(10x^2 + 99x – 5) ÷ (x + 10) = A. 10x – 1 remainder 5 B. 10x + 4 remainder –1 C. 10x remainder 8 D. 10x + 1 remainder 4
(10x^2 + 99x – 5) ÷ (x + 10) =(10x^2/x + 10) + (99x/x + 10) + (-5/x + 10) = 10x - 1 remainder 5
Question|Asked by LAILANI17
Asked 1/29/2018 12:08:42 AM
Updated 1/29/2018 2:42:19 AM
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Edited by Masamune [1/29/2018 2:42:19 AM]
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(10x^2 + 99x – 5) ÷ (x + 10)
=(10x^2/x + 10) + (99x/x + 10) + (-5/x + 10)
= 10x - 1 remainder 5
Added 1/29/2018 2:42:08 AM
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