Add the polynomials below. (6x3 + 8x2 - 2x + 4) + (10x3 + x2 + 11x + 9) A. 16x6 + 9x4 + 9x2 + 13 B. 16x3 + 9x2 + 9x3 + 13 C. 60x6 + 8x2 + 9x + 13 D. 16x3 + 9x2 + 9x + 13
(6x^3 + 8x^2 - 2x + 4) + (10x^3 + x^2 + 11x + 9) = 16x^3 + 9x^2 + 9x + 13
Question
Updated 8/12/2014 2:09:27 AM
Rating
3
(6x^3 + 8x^2 - 2x + 4) + (10x^3 + x^2 + 11x + 9) = 16x^3 + 9x^2 + 9x + 13
Confirmed by jeifunk [8/12/2014 2:12:49 AM]

Questions asked by the same visitor
(5x2 + 2x + 11) - (7 + 4x - 2x2) A. 9 - 2x - 2x2 B. 3x2 - 2x + 4 C. 3x2 + 6x + 4 D. 7x2 - 2x + 4 User: Find the difference. (6x3 + 7x + 12) - (3x2 + 8x + 8) A. 6x2 + 15x + 20 B. 6x3 - 3x2 - x + 4 C. 6x3 - 3x2 + 15x + 20 D. 6x3 - x + 4
Weegy: the answer is D. (3x-4)(2x+5) well, when u solve this kind of problems, u can check the answer by multiplying the FACTORS. here, (3x-4)(2x+5)=6x2 + 7x - 20 however, while solving it, the steps r as follows:- 1. first u multiply 6 with 20. [ This gives 120 2.now, u try to find two numbers, which are factors of 120, and give the difference of 7. here, they r 15 n 8. 3. then u do it as, 6x2 + 15x-8x - 20 =3x(2x+5)-4(2x+5) =(3x-4)92x+5) ] User: Find the difference. (9x2 + 10x + 4) - (9x2 + 5x - 1) A. 5x + 5 B. 15x + 3 C. x2 + 5x + 5 D. x2 + 15x + 3 (More)
Question
Updated 6/3/2014 10:46:38 PM
(5x^2 + 2x + 11) - (7 + 4x - 2x^2)
= 5x^2 + 2x + 11 - 7 - 4x + 2x^2
= 7x^2 - 2x + 4
Confirmed by yumdrea [6/3/2014 10:48:53 PM]
(6x^3 + 7x + 12) - (3x^2 + 8x + 8)
= 6x^3 + 7x + 12 - 3x^2 - 8x - 8
= 6x^3 - 3x^2 - x + 4
Confirmed by yumdrea [6/3/2014 10:49:47 PM]
(9x^2 + 10x + 4) - (9x^2 + 5x - 1)
= 9x^2 + 10x + 4 - 9x^2 - 5x + 1
= 5x + 5
Confirmed by yumdrea [6/3/2014 10:53:35 PM]
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