Two gears have 40 and 120 teeth. If driver rotates at 1000 rpm, determine speed of driven gear.

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Teeth: T1 = 40, T2 = 120, N1 = 1000 rpm Speed of driven: N2 = (T1/T2) * N1 = (40/120)*1000 = 333.33 rpm

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Asked 37 days ago|1/29/2026 6:02:55 AM

Updated 37 days ago|1/29/2026 6:29:02 AM

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cruz30

Teeth: T1 = 40, T2 = 120, N1 = 1000 rpm
Speed of driven: N2 = (T1/T2) * N1 = (40/120)*1000 = 333.33 rpm

Added 37 days ago|1/29/2026 6:28:35 AM

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Flora1988

Speed of Driven Gear = X rpmSo, 40 * 1000 = 120 * X40000 = 120X X = 40000 / 120 X = 333.33 rpm.
Therefore, the speed of the driven gear is 333.33 rpm.

Added 37 days ago|1/29/2026 6:29:02 AM

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