Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23. A. r = –12, s = 9 B. r = 4, s = 3 C. r = 12, s = 0 D. r = –1, s = –3
3r – 4s = 0 2r + 5s = 23 (3r – 4s = 0) * 5 15r - 20s = 0 (2r + 5s = 23) * 4 8r + 20s = 92 (15r - 20s = 0) + (8r + 20s = 92) 23r = 92 r = 92/23 r = 4 3(4) – 4s = 0 12 - 4s = 0 -4s = -12 s = -12/-4 s = 3 Solution set: r = 4, s = 3
Question
Updated 12/7/2017 8:29:38 PM
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3
3r – 4s = 0
2r + 5s = 23

(3r – 4s = 0) * 5
15r - 20s = 0
(2r + 5s = 23) * 4
8r + 20s = 92

(15r - 20s = 0) + (8r + 20s = 92)
23r = 92
r = 92/23
r = 4

3(4) – 4s = 0
12 - 4s = 0
-4s = -12
s = -12/-4
s = 3

Solution set: r = 4, s = 3

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