Determine probability of 3 successes in 5 Bernoulli trials with p = 0.6.

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n = 5, k = 3, p = 0.6 P(X=3) = C(5,3) * (0.6)^3 * (0.4)^2 C(5,3) = 10 P = 10 * 0.216 * 0.16 = 10 * 0.03456 = 0.3456

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Asked 37 days ago|3/6/2026 9:19:12 AM

Updated 37 days ago|3/6/2026 9:42:31 AM

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cruz30

n = 5, k = 3, p = 0.6
P(X=3) = C(5,3) * (0.6)^3 * (0.4)^2
C(5,3) = 10
P = 10 * 0.216 * 0.16 = 10 * 0.03456 = 0.3456

Added 37 days ago|3/6/2026 9:41:53 AM

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Salas1987

P(X=3) = 10 * 0.216 * 0.16 = 0.3456. Therefore, the probability of 3 successes in 5 Bernoulli trials with p = 0.6 is 0.3456.

Added 37 days ago|3/6/2026 9:42:31 AM

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