A company is interested in buying a new machine to replace their outdated equipment. However, before committing to the purchase, the company asks the manufacturer to provide data on a certain machine's efficiency. The data suggests that with a supplied energy at a rate of 1,600 W, the machine will do useful work at a rate of 1,540 W. What's the efficiency of this particular machine?
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A company is interested in buying a new machine to replace their outdated equipment. However, before committing to the purchase, the company asks the manufacturer to provide data on a certain machine's efficiency. The data suggests that with a supplied energy at a rate of 1,600 W, the machine will do useful work at a rate of 1,540 W. The efficiency of this particular machine is 96.25% Efficiency = Output/ Input = 1540/1600 *100= 96.25%
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Updated 59 days ago|11/21/2020 11:49:55 PM
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A company is interested in buying a new machine to replace their outdated equipment. However, before committing to the purchase, the company asks the manufacturer to provide data on a certain machine's efficiency. The data suggests that with a supplied energy at a rate of 1,600 W, the machine will do useful work at a rate of 1,540 W. The efficiency of this particular machine is 96.25% Efficiency = Output/ Input = 1540/1600 *100= 96.25%
Added 59 days ago|11/21/2020 11:49:55 PM

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If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, the volume at 50°C is 0.002010837 m^3. Density of mercury is 13545 kg/m^3 at 20 deg.C ; 13472 kg/m^3 at 50 deg, C ; M = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg ; Let V m^3 = volume at 50 deg. C ; (13472 kg/m^3)*(V m^3) = 27.09 kg ; V = 27.09/13472 = 0.002010837 m^3.
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Updated 228 days ago|6/6/2020 11:06:47 AM
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