Calculate gravitational force between two 80 kg masses separated by 0.6 m.

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Given: m = m = 80 kg r = 0.6 m G = 6.674×10 ¹¹ N·m²/kg² F = G m m / r² F = (6.674×10 ¹¹ × 80 × 80) / 0.6² F = (6.674×10 ¹¹ × 6400) / 0.36 F = 4.271×10 / 0.36 F = 1.19×10 N Answer: 1.19×10 N

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Asked 34 days ago|2/1/2026 10:34:31 AM

Updated 33 days ago|2/2/2026 5:56:38 AM

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cruz30

Given:
m = m = 80 kg
r = 0.6 m
G = 6.674×10 ¹¹ N·m²/kg²
F = G m m / r²
F = (6.674×10 ¹¹ × 80 × 80) / 0.6²
F = (6.674×10 ¹¹ × 6400) / 0.36
F = 4.271×10 / 0.36
F = 1.19×10 N
Answer: 1.19×10 N

Added 33 days ago|2/2/2026 5:56:09 AM

This answer has been confirmed as correct and helpful.

Salas1987

F = G * (m1 * m2) / r^2,

Given m1 = 80 kg, m2 = 80 kg, and r = 0.6 m.
F = (6.674 × 10^-11 N.m2/kg2) * (80 kg * 80 kg) / (0.6 m)^2. F = (6.674 × 10^-11) * (6400) / 0.36 N. F = (4.27136 × 10^-7) / 0.36 N. F = 1.18648 × 10^-6 N.

Added 33 days ago|2/2/2026 5:56:38 AM

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cruz30

Given:
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cruz30

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Added 33 days ago|2/2/2026 5:48:07 AM

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Added 33 days ago|2/2/2026 5:49:57 AM

Deleted by Salas1987 [2/2/2026 5:50:04 AM]

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