The following quote is an example of what figurative language?
"He now dug into the poor clergyman's heart, like a miner searching for gold."
A. Simile
B. Personification
C. Hyperbole
D. Metaphor

"He now dug into the poor clergyman's heart, like a miner searching for gold." - is an example of a Simile.

Question

Asked 12/18/2017 12:43:15 PM

Updated 12/18/2017 3:57:31 PM

1 Answer/Comment

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3

"He now dug into the poor clergyman's heart, like a miner searching for gold." - is an example of a Simile.

Added 12/18/2017 3:57:31 PM

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Simplify (–8q^3r^4s^2)^2 = ?
A. –64q^9r^16s^4
B. 64q^6r^8s^4
C. –64q^6r^8s^4
D. 64q^9r^16s^4

Question

Not Answered

Updated 140 days ago|12/30/2018 10:58:59 AM

2 Answers/Comments

(–8q^3r^4s^2)^2 = 64q^6r^8s^4

Added 12/11/2017 3:59:18 PM

This answer has been confirmed as correct and helpful.

Find the value of x in the equation 2(x – 3) + 5x = 5(2x + 6).
A. –12
B. 12
C. –2
D. 2 **Weegy:**
2(x – 3) + 5x = 5(2x + 6);
2x - 6 + 5x = 10x + 30 ;
7x - 6 = 10x + 30 ;
7x - 10x = 30 + 6 ;
-3x = 36 ;
x = 36/-3 ;
x = -12
**User:** Find the value of n in the equation 6.2n – 3.7n = 85 + 45.
A. 13.13
B. 16
C. 52
D. 325 (More)

Question

Updated 12/12/2017 1:44:46 AM

1 Answer/Comment

6.2n – 3.7n = 85 + 45

2.5n = 130

n = 130/2.5

n = 52

2.5n = 130

n = 130/2.5

n = 52

Added 12/12/2017 1:44:46 AM

This answer has been confirmed as correct and helpful.

There are two factories in the town of Lemming. Factory A has 4 times as many workers as Factory B. Factory A has 1,160 workers. How many workers does Factory B have?
A. 1,450
B. 5,800
C. 4,640
D. 290

Question

Not Answered

Updated 12/12/2017 1:42:23 AM

1 Answer/Comment

Factory A has 4 times as many workers as Factory B. Factory A has 1,160 workers. Factory B has **290** workers.

1,160/4 = 290

1,160/4 = 290

Added 12/12/2017 1:42:23 AM

This answer has been confirmed as correct and helpful.

Solve the system of equations 3y + 2z = 12 and y – z = 9.
A. y = 6, z = 15
B. y = –6, z = 15
C. y = 6, z = –3
D. y = 24, z = 15

Question

Updated 12/12/2017 1:53:18 AM

1 Answer/Comment

3y + 2z = 12

y – z = 9

y = z + 9

3(z + 9) + 2z = 12

3z + 27 + 2z = 12

5z + 27 = 12

5z = 12 - 27

5z = -15

z = -15/5

z = -3

y - (-3) = 9

y + 3 = 9

y = 9 - 3

y = 6

Solution set: y = 6, z = -3

y – z = 9

y = z + 9

3(z + 9) + 2z = 12

3z + 27 + 2z = 12

5z + 27 = 12

5z = 12 - 27

5z = -15

z = -15/5

z = -3

y - (-3) = 9

y + 3 = 9

y = 9 - 3

y = 6

Solution set: y = 6, z = -3

Added 12/12/2017 1:53:18 AM

This answer has been confirmed as correct and helpful.

Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20.
A. x = –10, y = 20
B. x = 10, y = 20
C. x = 2, y = 12
D. x = –6, y = 4

Question

Updated 12/12/2017 1:48:29 AM

1 Answer/Comment

2x + 3y = 40

–2x + 2y = 20

(2x + 3y = 40) + (–2x + 2y = 20)

5y = 60

y = 60/5

y = 12

2x + 3(12) = 40

2x + 36 = 40

2x = 40 - 36

2x = 4

x = 4/2

x = 2

Solution set: x = 2, y = 12

–2x + 2y = 20

(2x + 3y = 40) + (–2x + 2y = 20)

5y = 60

y = 60/5

y = 12

2x + 3(12) = 40

2x + 36 = 40

2x = 40 - 36

2x = 4

x = 4/2

x = 2

Solution set: x = 2, y = 12

Added 12/12/2017 1:48:29 AM

This answer has been confirmed as correct and helpful.

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