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Find the sum of (2p^5+3-4p^2) and (-8+14p^2+10p^5). Here are my options 12p5+10p2+5 12p5+10p2-5 12p5-10p2-5 12p5+18p2-5
(2p^5+3-4p^2) + (-8+14p^2+10p^5) = 12p^5 + 10p^2 - 5
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Asked 7/25/2016 3:01:36 PM
Updated 7/25/2016 8:57:55 PM
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(2p^5+3-4p^2) + (-8+14p^2+10p^5) = 12p^5 + 10p^2 - 5
Added 7/25/2016 8:57:55 PM
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