Is the inequality below sometimes, always, or never true? -2(2x + 9)

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Is the inequality below sometimes, always, or never true? -2(2x + 9) > -4x + 9 A. always B. sometimes C. never

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Asked 10/27/2013 11:31:36 AM

Updated 9/1/2014 11:31:37 AM

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Flagged by jeifunk [9/1/2014 11:31:37 AM]

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User: Is the inequality below sometimes, always, or never true? -2(2x + 9) > -4x + 9 A. always B. sometimes C. never

Weegy: The answer is x=-6,2. [ [ [ x^(2)-12=-4x Since -4x contains the variable to solve for, move it to the left-hand side of the equation by adding 4x to both sides. x^(2)-12+4x=0 Reorder the polynomial x^(2)-12+4x alphabetically from left to right, starting with the highest order term. x^(2)+4x-12=0 In this problem 6*-2=-12 and 6-2=4, so insert 6 as the right hand term of one factor and -2 as the right-hand term of the other factor. (x+6)(x-2)=0 Set each of the factors of the left-hand side of the equation equal to 0. x+6=0_x-2=0 Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides. x=-6_x-2=0 Set each of the factors of the left-hand side of the equation equal to 0. x=-6_x-2=0 Since -2 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2 to both sides. x=-6_x=2 The complete solution is the set of the individual solutions. x=-6,2 ] ] ]
jdevlin2414|Points 82|

User: Solve for t: S=5r^2t

Weegy: Solve for t: S=5r^2t is S-5 r^2 t = 0
Expert answered|jeifunk|Points 11050|

Question

Asked 10/27/2013 11:31:36 AM

Updated 9/1/2014 11:31:37 AM

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This conversation has been flagged as incorrect.

Flagged by jeifunk [9/1/2014 11:31:37 AM]

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jeifunk

S=5r^2t
5r^2t = s
5r^2t/5r^2 = s/ 5r^2t
t = s/5r^2

Added 9/1/2014 11:31:37 AM

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Find the least common multiple of x3 - x2 + x - 1 and x2 - 1. Write the answer in factored form. A. (x + 1)2(x - 1) B. (x + 1)(x - 1)(x2 + 1) C. (x3 - x2 + x - 1)(x2 - 1) D. (x + 1)(x - 1)(x2 - 1)

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Updated 5/7/2014 9:17:51 PM

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yeswey

x^3 - x^2 + x - 1
= x^2(x - 1) + (x - 1)
= (x^2 + 1)(x - 1);
x^2 - 1 = (x + 1)(x - 1)
So, The least common multiple of x^3 - x^2 + x - 1 and x^2 - 1 is (x + 1)(x - 1)(x^2 + 1).

Added 5/7/2014 9:11:58 PM

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Confirmed by jeifunk [5/7/2014 9:12:10 PM]

yeswey

(d^2 + d - 30)/(d^2 + 3d - 40) + (d^2 + 14d + 48)/(d^2 - 2d - 48)
= (d - 5)(d + 6)/(d - 5)(d + 8) + (d + 6)(d + 8)/(d + 6)(d - 8)
= (d + 6)/(d + 8) + (d + 8)/(d - 8)
= (d + 6)(d - 8)/(d + 8)(d - 8) + (d + 8)(d + 8)/(d + 8)(d - 8)
= (d^2 - 2d - 48)/(d^2 - 64) + (d^2 + 16d + 64)/(d^2 - 64)
= (2d^2 + 14d + 16)/(d^2 - 64)

Added 5/7/2014 9:17:51 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [5/7/2014 9:20:31 PM]

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