What are the zeros of this function: y=16x^2+40x+25?

Question

Asked 8/5/2013 2:09:45 PM

Updated 8/28/2014 2:13:55 AM

1 Answer/Comment

Flagged by andrewpallarca [8/28/2014 2:13:55 AM]

Question

Asked 8/5/2013 2:09:45 PM

Updated 8/28/2014 2:13:55 AM

1 Answer/Comment

Flagged by andrewpallarca [8/28/2014 2:13:55 AM]

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3

y = 16x^2 + 40x + 25;

(4x + 5)^2 = 0;

4x + 5 = 0; 4x = -5; x = -5/4

The zeros of this function: y=16x^2+40x+25 is -5/4

(4x + 5)^2 = 0;

4x + 5 = 0; 4x = -5; x = -5/4

The zeros of this function: y=16x^2+40x+25 is -5/4

Added 8/28/2014 2:13:50 AM

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