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4. What are the points of discontinuity? Are they all removable? Please show your work. y=(x-5)/x^2-6x+5
y=(x-5)/x^2-6x+5 when x^2-6x+5 = 0 (x - 1)(x - 5) = 0 x = 1 or x = 5 x = 1 or 5 are the points of discontinuity.
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Asked 12/29/2014 9:51:23 PM
Updated 12/29/2014 10:19:47 PM
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y=(x-5)/x^2-6x+5
when x^2-6x+5 = 0
(x - 1)(x - 5) = 0
x = 1 or x = 5
x = 1 or 5 are the points of discontinuity.
Added 12/29/2014 10:19:47 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [12/30/2014 8:48:41 AM]
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