What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)? (-10.5, 5) (-10.5, 7) (-2.5, 7)

Question and answer

Question

Asked 11/7/2014 8:24:39 AM

Updated 11/15/2014 2:39:44 PM

1 Answer/Comment

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/15/2014 2:39:44 PM]

Get an answer

Search for an answer or ask Weegy.

Original conversation

User: What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)? (-10.5, 5) (-10.5, 7) (-2.5, 7)

Weegy: The midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2) is (-10.5, 5).

((x1+x2)/2, (y1+y2)/2);

= ((-8 - 13)/2, (12 - 2)/2)

= (-21/2, 10/2)

= (-10.5, 5)

User: What is the length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12? 13 15 17

Weegy: The length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12 is 13.

User: Find the midpoint of the line segment whose endpoints are (3, 10) and (7, 8). (2, 1) (5, 9) (11, 12)

Weegy: Find the midpoint of the line segment whose endpoints are (3, 10) and (7, 8) is: (5, 9).

M = [(x2 + x1)/2] , [(y2 + y1)/2];

= [(3 + 7)/2] , [(10 + 8)/2];

= (10, 2) , (18, 2);

= (5, 9)

User: What is the equation of a circle whose center is at the origin and whose radius is 16? x2 + y2 = 4 x2 + y2 = 16 x2 + y2 = 256

Question

Asked 11/7/2014 8:24:39 AM

Updated 11/15/2014 2:39:44 PM

1 Answer/Comment

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/15/2014 2:39:44 PM]

New answers

Rating

yeswey

The equation of a circle whose center is at the origin and whose radius is 16 is: x^2 + y^2 = 256

Added 11/8/2014 4:10:30 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/15/2014 2:39:54 PM]

Comments

There are no comments.

Add an answer or comment

Questions asked by the same visitor

Find the center of the following equation. x 2 + y 2 + 8 x - 6 y - 15 = 0

(More)

Question

Updated 11/10/2014 11:24:59 PM

1 Answer/Comment

janezeshun

x^2 + y^2 + 8x - 6y - 15 = 0
(x + 4)^2 - 16 + (y - 3)^2 - 9 - 15 = 0
(x + 4)^2 + (y - 3)^2 = 40
(-4 , 3) is the center of equation.:x^2 + y^2 + 8x - 6y - 15 = 0 .

Added 11/10/2014 11:24:59 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/11/2014 12:51:23 AM]

What is the solution set of 2x(x - 1) = 3? User: Which of the following constants can be added to x2 - 10x to form a perfect square trinomial? 10 25 100 User: Write the quadratic equation in factored form. Be sure to write the entire equation. x2 + x - 12 = 0

Weegy: (x+4)(x-3)=0 User: If the quadratic formula is used to find the solution set of 3x 2 + 4x - 2 = 0, what are the solutions? User: What is the value of b2 - 4ac for the following equation? 2x2 + 3x = -1 0 1 17 Weegy: The answer is: b.1 [smile] User: What is the solution set of 7x 2 + 3x = 0? {0, 3/7} {0, -3/7} {0, -4/7} Weegy: The solution set of 7x^2 + 3x = 0 is: B. {0, -3/7}. User: What is the solution set of x 2 + 5x + 1 = 0? User: What is the solution set of (3x - 1)2 = 5? (More)

Question

Not Answered

Updated 11/11/2014 7:37:43 AM

2 Answers/Comments

yeswey

(3x - 1)^2 = 5
3x - 1 = ± sqrt 5
3x = 1 ± sqrt 5
x = (1 ± sqrt 5)/3

Added 11/11/2014 7:35:35 AM

This answer has been confirmed as correct and helpful.

yeswey

x^2 + 5x + 1 = 0
a = 1, b = 5, c = 1
discriminant = b^2 - 4ac = 25 - 4 = 21
x = (-5 ± sqrt 21)/2

Added 11/11/2014 7:37:43 AM

This answer has been confirmed as correct and helpful.

The radius of the circle whose equation is (x + 4)² + (y - 2)² = 36 is 36 18 6

Weegy: If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its radius is 6. User: The distance between the points (5, -2) and (-7, 3) is 5 29 13 (More)

Question

Updated 11/12/2014 10:56:02 PM

1 Answer/Comment

janezeshun

The distance between the points (5, -2) and (-7, 3) is 13 .
Let the distance is d
d^2 = (-7-5)^2 + {3 - (-2)}^2
d^2 = 144 + 25
d^2 = 169
d = 13

Added 11/12/2014 10:45:36 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/12/2014 10:56:22 PM], Rated good by jeifunk

Farsightedness is corrected with a convex concave lens.

Weegy: Farsightedness is corrected with a Convex lens. (More)

Question

Expert Answered

Updated 11/4/2014 9:21:02 AM

0 Answers/Comments

The center of a circle is at the origin. An endpoint of a diameter of the circle is at (-3, -4). How long is the diameter of the circle? 5 10 25

(More)

Question

Not Answered

Updated 11/9/2014 4:33:59 AM

1 Answer/Comment

janezeshun

The center of a circle is at the origin. An endpoint of a diameter of the circle is at (-3, -4). The diameter of the circle is 10.
Let the radius is r
r^2 = (-3)^2 + (-4)^2
r^2 = 25
r = 5
diameter = 2r = 2*5 = 10

Added 11/9/2014 4:33:59 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/15/2014 2:40:40 PM], Rated good by andrewpallarca

40,401,279

questions answered