Lori rented a car for one day. The daily rental rate was $12.50 plus 25 cents per mile. The total cost of her rental was $46. How many miles did she drive that day?
A. 46
B. 134
C. 50
D. 96

Lori rented a car for one day. The daily rental rate was $12.50 plus 25 cents per mile. The total cost of her rental was $46. Lori drove 134 miles that day: $46 - 12.50 = $33.50. $33.50 / 0.25 = 134.

Question

Asked 1/19/2018 2:05:52 PM

Updated 9/6/2021 1:23:47 PM

1 Answer/Comment

s

Rating

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Lori rented a car for one day. The daily rental rate was $12.50 plus 25 cents per mile. The total cost of her rental was $46. Lori drove 134 miles that day:

$46 - 12.50 = $33.50.

$33.50 / 0.25 = 134.

$46 - 12.50 = $33.50.

$33.50 / 0.25 = 134.

Added 9/6/2021 1:23:47 PM

This answer has been confirmed as correct and helpful.

Multiply (2m + 3)(m2 – 2m + 1).
A. 2m3 – m2 – 4m + 3
B. 2m3 – 7m2 – 4m + 2
C. 2m3 – m2 – 10m + 3
D. 2m3 – m2 – 8m + 3

Question

Not Answered

Updated 1/19/2018 7:12:36 PM

1 Answer/Comment

(2m + 3)(m^2 – 2m + 1)

= 2m^3 - 4m^2 + 2m + 3m^2 - 6m + 3

= 2m^3 - m^2 - 4m + 3

= 2m^3 - 4m^2 + 2m + 3m^2 - 6m + 3

= 2m^3 - m^2 - 4m + 3

Added 1/19/2018 7:12:36 PM

This answer has been confirmed as correct and helpful.

Solve the following system by any method.
–8x – 8y = 0
–8x + 2y = –20
A. (0, –2)
B. (–2, 2)
C. (2, –2)
D. (2, 2)

Question

Updated 1/19/2018 7:35:04 PM

1 Answer/Comment

–8x – 8y = 0

–8x + 2y = –20

(–8x + 2y = –20) - (–8x – 8y = 0)

10y = -20

y = -20/10

y = -2

–8x – 8(-2) = 0

-8x + 16 = 0

-8x = -16

x = -16/-8

x = 2

Solution set: (2, -2)

–8x + 2y = –20

(–8x + 2y = –20) - (–8x – 8y = 0)

10y = -20

y = -20/10

y = -2

–8x – 8(-2) = 0

-8x + 16 = 0

-8x = -16

x = -16/-8

x = 2

Solution set: (2, -2)

Added 1/19/2018 7:35:04 PM

This answer has been confirmed as correct and helpful.

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