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A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator supplies a voltage of 42 V, what is the magnitude of the current? A. 2 A B. 1.33 A C. 1.75 A D. 3 A
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A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator supplies a voltage of 42 V, the magnitude of the current is 3A . R = r1+r2 , R = 10+4 =14 ohm , V=IR , 42 = I*14 , I = 42/14 =3A.
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Asked 10/16/2018 11:22:27 AM
Updated 269 days ago|12/22/2020 3:24:55 PM
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A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator supplies a voltage of 42 V, the magnitude of the current is 3A .
R = r1+r2 , R = 10+4 =14 ohm , V=IR , 42 = I*14 , I = 42/14 =3A.
Added 269 days ago|12/22/2020 3:24:55 PM
This answer has been confirmed as correct and helpful.
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