Solve the system algebraically. Check your work. 5x + 2y = 10 3x + 2y = 6
5x + 2y = 10 ; 3x + 2y = 6; (3x + 2y = 6) - (5x + 2y = 10) ; -2x = -4 ; x = -4/-2 ; x = 2 ; 5(2) + 2y = 10 ; 10 + 2y = 10 ; 2y = 10 - 10 ; 2y = 0 ; y = 0/2 ; y = 0 ; Solution set: (2, 0)
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Updated 5/30/2018 11:59:30 AM
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5x + 2y = 10 ;
3x + 2y = 6;

(3x + 2y = 6) - (5x + 2y = 10) ;
-2x = -4 ;
x = -4/-2 ;
x = 2 ;

5(2) + 2y = 10 ;
10 + 2y = 10 ;
2y = 10 - 10 ;
2y = 0 ;
y = 0/2 ;
y = 0 ;

Solution set: (2, 0)

Questions asked by the same visitor
Solve the system algebraically. 2x+ y - 10 = 0 x - y - 4 = 0 What is the value of y? 1/3 2/3 14/3
Weegy: The solution for 2x+y-10=0, x - y - 4 = 0 is x = 14/3 ,y = 2/3. From 2x + y - 10 = 0 ,we can get y = 10-2x put y= 10 - 2x into the 2th equation x - y - 4 = 0 x -(10 -2x) - 4 = 0 3x = 14 x =14/3 y= 10 -2x y= 10 - 2*14/3 y= 2/3 User: Solve the system algebraically. 4x - 5y = 3 x = 3 - y What is the value of x? 9/7 24/14 33/14 (More)
Question
Updated 11/6/2014 7:42:31 PM
4x - 5y = 3
x = 3 - y
substitute x in the first equation the result is:
4(3 - y) - 5y = 3
12 - 4y - 5y = 3
-9y = 3 - 12 = -9
y = -9/-9 = 1
x = 2
The value of x is 2.
Confirmed by jeifunk [11/6/2014 7:42:39 PM]
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Question
Updated 11/6/2014 10:59:37 PM
The equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4x + y - 2 = 0 is: 4x + y = 13
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Updated 11/13/2014 12:55:19 PM
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