what are the dimensions of a rectangle if the area of a rectangle is 33 yd^2 and the length of the rectangle is 5yd less than twice the width?
Let w be the width of the rectangle, its length is: 2w - 5. Rectange area = width x length = w(2w - 5) = 33 2w^2 - 5w - 33 = 0 (w + 3)(2w - 11) = 0 w = -3 (not possible) or w = 11/2 yd. length = 2(11/2) - 5 = 11 - 5 = 6 yd.
Updated 5/19/2014 12:22:59 AM
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Let w be the width of the rectangle, its length is: 2w - 5.
Rectange area = width x length = w(2w - 5) = 33
2w^2 - 5w - 33 = 0
(w + 3)(2w - 11) = 0
w = -3 (not possible) or w = 11/2 yd.
length = 2(11/2) - 5 = 11 - 5 = 6 yd.
Confirmed by jeifunk [5/19/2014 4:52:39 AM]

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