Two dice are rolled. Probability that the sum is a multiple of 4 or 6.

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Sums multiples of 4: 4,8,12 outcomes: 3+5+1=9 Sums multiples of 6: 6,12 outcomes: 5+1=6 Overlap (sum=12) = 1 Total favorable = 9+6- 1=14 Total outcomes = 36 Probability = 14/36 = 7/18

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Asked 12 days ago|2/23/2026 9:23:44 AM

Updated 12 days ago|2/23/2026 9:59:38 AM

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cruz30

Sums multiples of 4: 4,8,12 outcomes: 3+5+1=9
Sums multiples of 6: 6,12 outcomes: 5+1=6
Overlap (sum=12) = 1
Total favorable = 9+6- 1=14
Total outcomes = 36
Probability = 14/36 = 7/18

Added 12 days ago|2/23/2026 9:59:17 AM

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Salas1987

P(A or B) = P(A) + P(B) - P(A and B) = 9/36 + 6/36 - 1/36 = (9 + 6 - 1)/36 = 14/36.
Simplify the fraction: 14/36 = 7/18.
The probability that the sum is a multiple of 4 or 6 is 7/18.

Added 12 days ago|2/23/2026 9:59:38 AM

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Updated 12 days ago|2/23/2026 8:15:08 AM

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