Simplify (x 2 y) 3.
(x^2y)^3 = x^6y^3
Question
Updated 4/27/2015 6:36:31 PM
s
Rating
3
(x^2y)^3
= x^6y^3
Confirmed by yumdrea [4/27/2015 6:49:41 PM]

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Updated 6/6/2015 11:49:44 AM
The expression (2x^2)^3 is equivalent to 8x^6.
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Evaluate (x + y )^0 for x = –3 and y = 5. User: Simplify. n^6 • n^5 ÷ n^4 • n^3 ÷ n^2 • n
Question
Updated 4/27/2015 12:02:13 PM
(x + y )^0 for x = –3 and y = 5;
(-3 + 5)^0
= 2^0
= 1
n^6 • n^5 ÷ n^4 • n^3 ÷ n^2 • n
= n^11 ÷ n^4 • n^3 ÷ n^2 • n
= n^7 • n^3 ÷ n^2 • n
= n^10 ÷ n^2 • n
= n^8 • n
= n^9
Find the product. 5x^2 · 2y^2
Weegy: 5x^2 * 2y^2 = 10x^2y^2 User: Find the product. x^5 · x^4 · x^3 (More)
Question
Updated 4/28/2015 3:09:20 AM
x^5*x^4*x^3
=x^9*x^3
=x^12
Confirmed by yumdrea [4/27/2015 8:14:20 PM]
Find the quotient. (4ab - 8a^2 + 12ac) ÷ (4a)
Weegy: (4ab - 8a 2 + 12ac)/(4a) = [(4a)(b - 2a + 3c)]/(4a) = -2a + b + 3c User: Find the sum and choose the correct answer. 2n^3 + 4n^2 - 7 and -n^3 - 8n - 2 -n 3 + 4n 2 - 8n - 9 n 3 + 4n 2 - 8n - 9 n 3 + 4n 2 - 8n - 5 n 3 - 4n 2 -9 User: How many terms are in the polynomial abcd + e - h^2? two three five six Weegy: There are THREE terms in the polynomial abcd + e - h^2. User: Find the product. y^5 · y^3 User: Write xyyzzz in exponential form. (More)
Question
Updated 4/28/2015 3:11:51 AM
2n^3+4n^2-7+(-n^3-8n-2)
=2n^3-n^3+4n^2-8n-7-2
=n^3+4n^2-8n-9
Confirmed by Andrew. [4/28/2015 3:12:33 AM]
y^5*y^3
=y^8
Confirmed by Andrew. [4/28/2015 3:12:35 AM]
xyyzzz
=xy^2z^3
Confirmed by Andrew. [4/28/2015 3:12:38 AM]
Find the product. 8y 3(-3y 2)
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Question
Updated 6/6/2015 11:52:24 AM
(k^3)^5
= k^15
Confirmed by jeifunk [6/6/2015 11:50:53 AM]
(fg)^9
=f^9g^9
Confirmed by jeifunk [6/6/2015 11:51:40 AM]
32,018,504
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