factor 25a2 - 70a + 49 completely
Question
Updated 5/6/2014 2:11:07 AM
Followed by yeswey, Edited by andrewpallarca [5/6/2014 1:18:58 AM]
Original conversation
User: factor 25a2 - 70a + 49 completely

Weegy: 25a^2 - 70a + 49 (5a - 7)*(5a - 7) or (5a - 7)^2

User: factor 4x2+ 8xy - 60y2 completely

Weegy: 4x^2+ 8xy - 60y^2 4(x^2 + 2xy - 15y) 4(x + 5y)(x - 3y)

Question
Updated 5/6/2014 2:11:07 AM
Followed by yeswey, Edited by andrewpallarca [5/6/2014 1:18:58 AM]
Rating
3
4x^2+ 8xy - 60y^2
= 4(x^2 + 2xy - 15y^2)
= 4(x + 5y)(x - 3y)
For the second question you also missed the power of y.
I am wondering if such answers need to be flagged.
yeswey, can you show us if the missing symbol is within the solution or the final answer?
The final answer is correct but in the second step he missed the power of y. I will post the answer again.
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factor 25a2 +9b2 + 30ab completely
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Updated 5/6/2014 1:02:45 AM
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5c^2 +30c + 45
= 5(c^2 + 6c + 9)
= 5(c + 3)^2
Confirmed by andrewpallarca [5/6/2014 1:03:38 AM]
factor 16ax + 4x2 +16a2 completely
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Question
Updated 5/6/2014 1:00:45 AM
13y^2 - 5yx - 8x^2 = (y - x)(13y + 8x)
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factor 3y4 - 2y2 - 5 completely
Weegy: Well, first you have to get a common denominator in your fractions. [ So, your equation becomes: 3y/4 - 4y/4 = 5 Then, we do the subtraction: -y/4 = 5 Then, let's get rid of the denominator by multiplying both sides by 4: -y = 20 Which becomes: y = -20 Unless you've typed something wrong, as far as I can tell, the answer is -20. ] User: factor 3y2 +7y + 4 completely Weegy: The factors of 3y^2 +7y + 4 are: (3y + 4)(y + 1) User: factor 450a2 +242c2 + 660ac completely Weegy: First they are all even so we know we can factor out at least a two and we also need tp rearrange to get in the proper sequence. [ so 2(2225a^2 +121c^2 +330ac) Now changing around 2(225a^2 + 330ac + 121 c^2) The portion inside the parentheses is a perfect square so the final answer is 2(15a+11c)^2 ] User: factor 2a2 + 2b2 - 5ab completely Weegy: 2a^2 + 2b^2 - 5ab, when factored is: (a-2b)(2a-b) User: factor 128x2 +96xy + 18y2 completely Weegy: (128 2) (96 x y) (18 y^2) = 442368 x y^3 User: factor y2x - yx - 20 completely (More)
Question
Updated 5/5/2014 7:52:18 PM
3y^4 - 2y^2 - 5 = (y^2 + 1)(3y^2 - 5)
Confirmed by alfred123 [5/5/2014 7:55:37 PM]
128x^2 +96xy + 18y^2
= 2(64x^2 + 48xy + 9y^2)
= 2(8x + 3y)(8x + 3y)
= 2(8x + 3y)^2
Confirmed by alfred123 [5/5/2014 7:55:39 PM]
factor c2 + 6c + 9 completely
Question
Updated 5/6/2014 12:50:30 AM
c^2 + 6c + 9 = (c + 3)^2
Confirmed by andrewpallarca [5/6/2014 12:55:04 AM]
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