Kepler’s Third Law of Orbital Motion states that you can approximate the period P (in Earth years) it takes a planet to complete one orbit of the sun using the function , P=d3/2 where d is the distance (in astronomical units, AU) from the planet to the sun. How many Earth years would it take for a planet that is 6.76 AU from the sun?
Question
Updated 4/21/2014 6:59:08 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [4/21/2014 6:56:57 PM]
Original conversation
User: how do you simplify 16^1/2

User: Kepler’s Third Law of Orbital Motion states that you can approximate the period P (in Earth years) it takes a planet to complete one orbit of the sun using the function , P=d3/2 where d is the distance (in astronomical units, AU) from the planet to the sun. How many Earth years would it take for a planet that is 6.76 AU from the sun?

Weegy: For a planet that is 6.76 AU from the sun it would take about B. 17.58 Earth years. [ ]

User:

Question
Updated 4/21/2014 6:59:08 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [4/21/2014 6:56:57 PM]
Rating
3
(16^1)/2 = 16/2 = 8
Confirmed by jeifunk [4/21/2014 7:00:09 PM]

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