A line passes through the origin and has a slope of –3. What is the equation of the line that is perpendicular to the first line and passes through the point (3, 4)?

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Asked 4/4/2014 8:34:11 AM

Updated 4/5/2014 9:11:07 AM

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tikuko|Points 0|

Question

Asked 4/4/2014 8:34:11 AM

Updated 4/5/2014 9:11:07 AM

2 Answers/Comments

This conversation has been flagged as incorrect.

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A line passes through the origin and has a slope of –3. The equation of the line that is perpendicular to the first line and passes through the point (3, 4) is y = 1/3x + 3

Added 4/5/2014 9:07:05 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [4/5/2014 2:20:01 PM]

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A line passes through the point (–2, 4), and its y-intercept is (0, –6). The equation of the line that is perpendicular to the first line and passes through the point (5, –4) is y = 1/5x - 5

First we need to find out the slope of the first line m = (-6 - 4)/(0 + 2) = -5; therefore, the slope for the required line is 1/5. Since the line pass through (5, -4), in point slope form is y + 4 = 1/5(x - 5), rewritten in slope intercept form is y = 1/5x - 5

First we need to find out the slope of the first line m = (-6 - 4)/(0 + 2) = -5; therefore, the slope for the required line is 1/5. Since the line pass through (5, -4), in point slope form is y + 4 = 1/5(x - 5), rewritten in slope intercept form is y = 1/5x - 5

Added 4/5/2014 9:11:07 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [4/5/2014 2:20:02 PM]

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