A. y |x – 5| – 5 B. y |x – 5| + 5 C. y |x + 5| + 5 D. y |x – 5| + 5
Question
Updated 7/27/2014 12:21:31 AM
Original conversation
User: A. y |x – 5| – 5 B. y |x – 5| + 5 C. y |x + 5| + 5 D. y |x – 5| + 5

patrick_hustla|Points 890|

User: What is the slope of the line that passes through the given points? (6, 2) and (7, 4)

User: What is the equation of the given line in standard form? Use integer coefficients. y = 5/7x - 12 A. -5x + 7y = -12 B. -5x - 7y = -84 C. -5x + 7y = -84 D. 5x + 7y = -84

Weegy: C. -5x + 7y = -84
asero1010|Points 4484|

User: What is the equation of the line in slope-intercept form? the line perpendicular to y = 1/3x + 5 through (2, 1) A. y = -1/3x + 7 B. y = -3x + 7 C. y = 1/3x + 7 D. y = 3x + 7

Weegy: D. y = -1/3x 7
nhesreen|Points 65|

User: Tickets to a concert are available online for \$20 each, plus a one-time handling fee of \$1.75. The total cost is a function of the number of tickets bought. What function rule models the cost of the concert tickets ( t )? Evaluate the function for 3 tickets. A. 1.75t + 20; \$25.25 B. 1.75t + 20; \$61.75 C. 20t + 1.75; \$25.25 D. 20t + 1.75; \$61.75

Weegy: The function rule models the cost of the concert tickets is:C.20t + 1.75; \$61.75
ashakr|Points 70|

User: What is the graph of the direct variation equation? y = - 4x

User: The function f(x) = x2. The graph of g(x) is f(x) translated to the left 6 units and down 5 units. What is the function rule for g(x)? A. g(x) = (x + 6)2 - 5 B. g(x) = (x - 5)2 + 6 C. g(x) = (x - 6)2 + 5 D. g(x) = (x + 5)2 - 6

Weegy: The function f(x) = x2. The graph of g(x) is f(x) translated to the left 6 units and down 5 units. What is the function rule for g(x). Answer is: A. g(x) = (x + 6)2 - 5

Question
Updated 7/27/2014 12:21:31 AM
Rating
3
The slope of the line that passes through the given points (6, 2) and (7, 4) is m = (4 - 2)/(7 - 6) = 2
Confirmed by andrewpallarca [7/27/2014 1:05:48 PM]
3
The equation of the line perpendicular to y = 1/3x + 5 through (2, 1) in slope intercept form is y = -3x + 7.
Confirmed by andrewpallarca [7/27/2014 1:05:58 PM]

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