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7x-4y=60 2x-5y=21 using elimination
Question
Asked 8/20/2013 12:51:43 PM
Updated 5/25/2014 11:58:39 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [5/25/2014 11:58:29 PM]
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User: 7x-4y=60 2x-5y=21 using elimination

Weegy: solve for y or x in one equation then, insert that into the other equation in place of the variable you solved for.
Expert answered|speedycross09|Points 162|

Question
Asked 8/20/2013 12:51:43 PM
Updated 5/25/2014 11:58:39 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [5/25/2014 11:58:29 PM]
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7x-4y=60 multiple 2 on both sides:
14x - 8y = 120 (equation 1)
2x-5y=21 multiple 7 on both sides:
14x - 35y = 147 (equation 2)
eqution 1 - equation 2 the result is:
27y = -27
y = -27/27 = -1;
7x-4(-1)=60,
7x + 4 = 60
7x = 60 - 4 = 56
x = 56/7 = 8;
The solution for the system 7x-4y=60 2x-5y=21 is (8, -1)
Added 5/25/2014 11:58:39 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/26/2014 12:42:55 AM]
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Questions asked by the same visitor
Use the elimination method to solve the system of linear equations 7x-4y=60 2x-5y=21
Weegy: solve for y or x in one side then insert that into the other equation (More)
Question
Expert Answered
Updated 5/25/2014 11:57:43 PM
1 Answer/Comment
7x-4y=60 multiple 2 on both sides:
14x - 8y = 120 (equation 1)
2x-5y=21 multiple 7 on both sides:
14x - 35y = 147 (equation 2)
eqution 1 - equation 2 the result is:
27y = -27
y = -27/27 = -1;
7x-4(-1)=60,
7x + 4 = 60
7x = 60 - 4 = 56
x = 56/7 = 8;
The solution for the system 7x-4y=60 2x-5y=21 is (8, -1)
Added 5/25/2014 11:57:43 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [9/4/2014 4:31:26 PM]
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