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The line that passes through (-1, -3) and (2, 1)
Question|Asked by 16jbrown
Asked 3/24/2016 12:54:28 PM
Updated 3/24/2016 11:24:05 PM
1 Answer/Comment
Flagged by arel [3/24/2016 11:23:46 PM]
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User: The line that passes through (-1, -3) and (2, 1)

Question|Asked by 16jbrown
Asked 3/24/2016 12:54:28 PM
Updated 3/24/2016 11:24:05 PM
1 Answer/Comment
Flagged by arel [3/24/2016 11:23:46 PM]
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The line that passes through (-1, -3) and (2, 1) is 4/3.
slope = (1 + 3)/(2 + 1) = 4/3
Added 3/24/2016 11:24:05 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [3/25/2016 12:08:04 AM], Rated good by jeifunk
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Questions asked by 16jbrown
(2a)3 = _____ This expression without exponents is?
Question|Asked by 16jbrown
Updated 3/25/2016 12:21:13 AM
2 Answers/Comments
This expression without exponents is 8a^3.
(2a)^3
= (2a)(2a)(2a)
= 8a^3
Added 3/24/2016 10:54:42 PM
This answer has been flagged as incorrect.
Flagged by Andrew. [3/25/2016 12:21:31 AM]
(2a)^3 = (2a)(2a)(2a)
This expression without exponents is (2a)(2a)(2a).
Added 3/25/2016 12:21:13 AM
This answer has been confirmed as correct and helpful.
Input in standard form the equation of the given line. The line that passes through (-2, 4) and is parallel to x - 2y = 6
Question|Asked by 16jbrown
Not Answered
Updated 3/27/2016 11:37:20 PM
1 Answer/Comment
The standard form the equation of the given line. The line that passes through (-2, 4) and is parallel to x - 2y = 6 is x - 2y = -10.
slope of x - 2y = 6 is 1/2;
y - 4 = 1/2(x + 2);
2y - 8 = x + 2;
x - 2y = -10
Added 3/27/2016 9:56:25 PM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [3/27/2016 11:37:21 PM], Rated good by Andrew.
subtract polynomials (-6.7x2 + 2.3xy + 5.2) - (-14.9x2 - 3.5xy + 7.1)
Question|Asked by 16jbrown
Updated 3/25/2016 7:41:38 AM
1 Answer/Comment
(-6.7x^2 + 2.3xy + 5.2) - (-14.9x^2 - 3.5xy + 7.1)

= -6.7x^2 + 14.9x^2 + 2.3xy + 3.5xy + 5.2 - 7.1;

= 8.2x^2 + 5.8xy + 1.9
Added 3/25/2016 7:41:38 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [3/25/2016 8:36:40 AM]
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