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A 3 kg block slides down a 35° incline. Friction coefficient is 0.25. Determine the acceleration and frictional force.
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Asked 16 days ago|1/29/2026 6:43:41 AM
Updated 16 days ago|1/29/2026 7:36:05 AM
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m = 3 kg, = 35°, = 0.25, g = 9.8
F_parallel = m g sin = 3 × 9.8 × sin35° = 16.8 N
F_friction = m g cos = 0.25 × 3 × 9.8 × cos35° = 7.6 N
Net force: F_net = F_parallel - F_friction = 16.8 - 7.6 = 9.2 N
Acceleration: a = F_net / m = 9.2 / 3 = 3.07 m/s²
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Added 16 days ago|1/29/2026 7:12:11 AM
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Added 16 days ago|1/29/2026 7:32:35 AM
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Added 16 days ago|1/29/2026 7:32:49 AM
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Added 16 days ago|1/29/2026 7:35:03 AM
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Added 16 days ago|1/29/2026 7:36:05 AM
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