Use the zero product property to find the solutions to the equation 2x^2 – x – 15 = x(x + 1).
2x^2 – x – 15 = x(x + 1) 2x^2 - x - 15 = x^2 + x 2x^2 - x^2 - x - x - 15 = 0 x^2 - 2x - 15 = 0 (x - 5)(x + 3) = 0 when x - 5 = 0 , x = 5 when x + 3 = 0 , x = -3
Question
Updated 3/3/2015 3:54:33 AM
Rating
3
2x^2 – x – 15 = x(x + 1)
2x^2 - x - 15 = x^2 + x
2x^2 - x^2 - x - x - 15 = 0
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
when x - 5 = 0 , x = 5
when x + 3 = 0 , x = -3
Confirmed by jeifunk [3/3/2015 8:13:18 AM]

Questions asked by the same visitor
What is the vertex and the equation of the axis of symmetry of the graph of y=x^2-6x-7?
Question
Updated 3/3/2015 4:10:42 AM
The vertex and the equation of the axis of symmetry of the graph of y=x^2-6x-7 is
vertex is (3 , -16) , symmetry = -16 .
symmetry = 6/2*1 = 3
when x = 3
y = 3^2 - 6*3 - 7
y = 9 - 18 - 7
y = -9 - 7
y = -16
Confirmed by jeifunk [3/3/2015 8:14:03 AM]
Use the zero product property to find the solutions to the equation x^2 – x – 6 = 0.
Question
Updated 3/3/2015 4:00:18 AM
x^2 – x – 6 = 0
(x - 3)(x + 2) = 0
when x - 3 = 0 , x = 3
when x + 2 = 0 , x = -2
Confirmed by jeifunk [3/3/2015 8:17:04 AM]
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