Given the sequence 7, 14, 28, 56, ..., which expression shown would give the tenth term?
Question
Updated 11/3/2014 8:52:02 PM
This conversation has been flagged as incorrect.
Flagged by janezeshun [11/3/2014 8:52:02 PM]
Original conversation
User: What is the next term of the following sequence? What is the next term of the following sequence? 20, 10, 5, 2, ...

User: If the sixth term of a sequence is 128 and the common ratio is 2, then what is the first term?

User: What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?

User: Given the sequence 7, 14, 28, 56, ..., which expression shown would give the tenth term?

Weegy: since it is multiplied by 2. the sequence is 7,14,28,56,112,224,448,896,1792,3584. The tenth expression is 3584.
conconn|Points 90|

User: 0.1, 0.01, 0.001, ... Find the common ratio for the following sequence.

Weegy: The sequence of the numbers 1, 0.1, 0.01, 0.001, 0.0001, 0.00001 is the geometric progression. The ratio of the current term to the preceding term is the constant equal to 1%2F10 for any two consecutive terms. [ The first term of this progression is equal to 1, the common ratio is equal to 1%2F10, or 0.1. This progression is a decreasing sequence: the next term is lesser than the previous one for any two consecutive terms. ]
matahari|Points 2630|

User: Simplify. 1.5m 7(-4m 5)2

Weegy: The simplified expression of 1.5m^7(-4m^5)^2 is: 24. m^17.
emdjay23|Points 2538|

User: Simplify. (-4a 3)3·a 4

rio8408|Points 400|

User: Simplify. (-4a 3)3·a 4

rio8408|Points 400|

User: (-4a 3)3·a 4 Simplify?

rio8408|Points 400|

User: What is the fifth term of a sequence whose first term is 5 and whose common ratio is 3?

Weegy: .. the fifth term of the geometric sequence 3/2 , 1 , 2/3 ,? In order to solve, you need to find the common ratio ... [ Fifth term of the sequence whose first term ..
chumz|Points 140|

User: Find the next term of the following sequence. 25, 10, 4, ...

User: Simplify.(y 3)5 · y 4

Weegy: that's not possible! what do you need to know. [s]
eitak1987|Points 55|

User: Simplify.(y^3)5 · y^4

Weegy: that's not possible! what do you need to know. [s]
eitak1987|Points 55|

User: Simplify.(-3ab3)4

bongche|Points 3864|

User: x8 ÷ x4 · x2 Simplify

User: Find the quotient. 23 ÷ 52

Weegy: 23^52 is about 6.454 * 10^70 or 64 duovigintillion.
eturker|Points 3037|

Question
Updated 11/3/2014 8:52:02 PM
This conversation has been flagged as incorrect.
Flagged by janezeshun [11/3/2014 8:52:02 PM]
Rating
0
If the sixth term of a sequence is 128 and the common ratio is 2, then the first term is 4 .
Let the first term is a
128 = a*2^(6 - 1)
128 = a*32
a = 128/32
a = 4

0
The seventh term of a sequence whose first term is 1 and whose common ratio is 3 is 729 .
Seventh term = 1*3^(7 - 1) = 3^6 = 729
0
The tenth term for the given the sequence 7, 14, 28, 56, is 7*2^9.
Common ratio = 56/28 = 28/14 = 14/7 = 2
Tenth term = 7*2^(10 - 1) = 7*2^9
0
(-4a^3)^3·a^4
= -64 a^9*a^4
= -64a^13

Confirmed by yumdrea [11/3/2014 9:03:27 PM]
0
The fifth term of a sequence whose first term is 5 and whose common ratio is 3 is 405 .
Fifth term = 5*3^(5 - 1) = 5*3^4 = 405
0
The next term of the following sequence 25, 10, 4, ... is 8/5 .
Common ratio = 4/10 = 10/25 = 2/5
Next term = 4*2/5 = 8/5
0
(y^3)^5 · y^4
= y^15*y^4
= y^19
Confirmed by yumdrea [11/3/2014 9:00:48 PM]
0
(-3ab^3)^4
= 81a^4b^12
Confirmed by yumdrea [11/3/2014 9:02:27 PM]
0
x^8 ÷ x^4 · x^2
= x^4*x^2
= x^6
Confirmed by yumdrea [11/3/2014 9:04:29 PM]
0
23 ÷ 52
= 23/52
= 0.4423076923

27,673,834
*
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