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find the product (n + 8)(n - 2)
Question
Asked 4/16/2014 2:43:40 PM
Updated 4/16/2014 3:13:29 PM
1 Answer/Comment
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Flagged by andrewpallarca [4/16/2014 3:13:29 PM]
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Original conversation
User: find the product (n + 8)(n - 2)

Weegy: Simplify n - {1 - [n - (1 - n) - 1]}. Solution: n- {1-[n-(1-n)-1]} = n- {1-[n-1+n-1]} = n- {1-[2n-2]} = n- {1-2n+2} = n- {3-2n} = n-3+2n = 3n-3
samth007|Points 105|

Question
Asked 4/16/2014 2:43:40 PM
Updated 4/16/2014 3:13:29 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [4/16/2014 3:13:29 PM]
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(n + 8)(n - 2);

n^2 - 2n + 8n - 16

= n^2 + 6n - 16
Added 4/16/2014 3:13:28 PM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
Evaluate h -2 g for h = 3 and g = 27
Question
Updated 4/16/2014 9:16:35 PM
1 Answer/Comment
When h = 3 and g = 27,
h -2g = 3 - 2(27) = 3 - 54 = - 51
Added 4/16/2014 9:16:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/16/2014 9:19:59 PM]
solve this equation (5x 2 + 2x - 3)(x - 1)
Question
Updated 4/16/2014 7:05:26 PM
1 Answer/Comment
(5x^2 + 2x - 3)(x - 1)
= 5x^3 - 5x^2 + 2x^2 - 2x - 3x + 3
= 5x^3 - 3x^2 - 5x + 3
Added 4/16/2014 7:05:26 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/16/2014 7:13:52 PM]
The legs of a right triangle measure 5 cm and 4 cm. Find the area.
Question
Updated 4/18/2014 1:47:01 AM
1 Answer/Comment
The legs of a right triangle measure 5 cm and 4 cm. Its area = 1/2*5*4 = 10 cm^2
Added 4/18/2014 1:47:01 AM
This answer has been confirmed as correct and helpful.
Find the product. 4x 3y(-2x 2y) -8x 6y -8x 5y -8x 5y 2 2x 5y 2
Question
Updated 10/20/2014 12:57:47 AM
1 Answer/Comment
4x^3y(-2x^2y)
= 4x^3*(-2x^2)*y*y
= -8x^5y^2
Added 10/20/2014 12:57:47 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [10/20/2014 1:05:30 AM], Rated good by jeifunk
A pair of vertical angles are acute. always sometimes never
Weegy: A pair of vertical angles are SOMETIMES acute. (More)
Question
Updated 4/14/2014 4:56:40 PM
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