A line passes through the origin and has a slope of –3. What is the equation of the line that is perpendicular to the first line and passes through the point (3, 4)?

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Asked 10/24/2013 2:53:06 PM

Updated 7/27/2014 12:29:22 AM

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Flagged by yeswey [7/27/2014 12:26:47 AM]

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Question

Asked 10/24/2013 2:53:06 PM

Updated 7/27/2014 12:29:22 AM

3 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by yeswey [7/27/2014 12:26:47 AM]

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A line passes through the origin and has a slope of –3. The equation of the line that is perpendicular to the first line and passes through the point (3, 4) is y = 1/3x + 3

Added 7/27/2014 12:26:28 AM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [7/27/2014 12:56:30 PM]

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The slope of a line is –4 and its y-intercept is (0, 4). The equation of the line that is perpendicular to the first line and passes through (–8, 2) is y = 1/4x + 4

Added 7/27/2014 12:28:03 AM

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Confirmed by yumdrea [7/27/2014 12:56:30 PM]

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The equation of the line that passes through (–2, –3) and is perpendicular to 2x – 3y = 6 is 3x + 2y = -12

Added 7/27/2014 12:29:22 AM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [7/27/2014 12:56:29 PM]

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