What is the length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12?
The length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12 is sqrt (5^2 + 12^2) = 13
Question
Updated 4/29/2015 9:05:10 PM
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The length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12 is sqrt (5^2 + 12^2) = 13
Confirmed by sujaysen [5/5/2015 10:04:10 AM]

Questions asked by the same visitor
3x+1 =7
Question
Updated 4/24/2015 11:18:07 AM
3x+1 =7
3x=7-1=6
x=6/3=2
Confirmed by sujaysen [4/30/2015 1:48:20 PM]
3x+1 =7
3x = 7 - 1
3x = 6
x = 6/3
x = 2
2x 2 - 2x - 1 = 0
Weegy: (2x - 1)(x + 5) = 0; 2x - 1 = 0; 2x = 0 + 1; 2x = 1; x = 1/2; x + 5 = 0; x = 0 - 5; x = -5; the solution set is (1/2, -5) User: x 2 + 5x + 4 = 0 Weegy: 2x - 1 User: 5x2 + 7x = 6 (More)
Question
Updated 5/4/2015 10:08:20 PM
2x^2 - 2x - 1 = 0
a = 2, b = -2, c = -1
b^2 - 4ac = (-2)^2 - 4(2)(-1) = 4 + 8 = 12
x = [-b ± sqrt (b^2 - 4ac)]/2a
= (2 ± sqrt 12)/4
= (2 ± 2 sqrt 3)/4
= (1 ± sqrt 3)/2
Confirmed by sujaysen [5/5/2015 9:59:11 AM]
x^2 + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 or x = -4
Confirmed by sujaysen [5/5/2015 9:59:38 AM]
5x^2 + 7x = 6
5x^2 + 7x - 6 = 0
(x + 2)(5x - 3) = 0
x = -2 or x = 3/5
Confirmed by sujaysen [5/5/2015 10:00:11 AM]
A parabola has a vertex at (-1, 0) and opens down. What is the equation of the parabola? y = -x2 - 1 y = -(x - 1)2 y = -(x + 1)2 User: Which of the following equations is of a parabola with a vertex at (3, 0)? y = (x - 3)2 y = (x + 3)2 y = x2 - 3 y = x2 + 3 User: Which of the following equations is of a parabola with a vertex at (3, 0)? y = (x - 3)2 y = (x + 3)2 y = x2 - 3 y = x2 + 3 User: A parabola whose equation is y = (x - 5)2 - 2 has a vertex at _____. (-5, -2) (-5, 2) (5, -2) (5, ...
Question
Updated 5/4/2015 8:30:18 AM
y = (x - 3)^2 is of a parabola with a vertex at (3, 0).
Confirmed by sujaysen [5/5/2015 10:04:59 AM]
A parabola whose equation is y = (x - 5)^2 - 2 has a vertex at (5, -2)
Confirmed by sujaysen [5/5/2015 10:07:52 AM]
y = x^2 + 3 is of a parabola with a vertex at (0, 3).
Confirmed by sujaysen [5/5/2015 10:08:17 AM]
Find the vertex of the parabola whose equation is y = -2x2 + 8x - 5. User: Find the vertex of the parabola whose equation is y = x2 + 6x + 2. User: y = -x2 - 4x - 3 User: Which of the following is a quadratic inequality? y
Weegy: y User: The dashed parabola is to the quadratic inequality as the is to the number line graph. Weegy: That would be open circle User: A parabola opens down if the value of is negative in the general form of the equation. (More)
Question
Updated 4/29/2015 9:56:42 PM
A parabola opens down if the value of "a" is negative in the general form of the equation.
Confirmed by Andrew. [4/30/2015 2:55:59 AM]
The vertex of the parabola whose equation is y = x^2 + 6x + 2 is (-3, -7).
Confirmed by Andrew. [4/30/2015 2:56:23 AM]
The vertex of the parabola whose equation is y = -x^2 - 4x - 3 is (-2, 1).
Confirmed by Andrew. [4/30/2015 2:56:42 AM]
Give the values of a, b, and c from the general form of the equation (2x + 1)(x - 2) = 0. User: Which of the following equations is quadratic? x(x2 + 1) = 0 5(4x + 2) = 3 (x + 3)(x + 4) = 5 User: Which of the following is the general form of the equation 5x2 - 20x = 15?
Weegy: The general form of the equation 5x^2 - 20x = 15 is 5x^2 - 20x - 15 = 0. User: The line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = -2. What is the value of "a"? User: Describe the translation of the graph of y = x2 that results in the graph of y = (x - 3)2. (More)
Question
Updated 4/29/2015 8:49:57 PM
(x + 3)(x + 4) = 5 is quadratic.
(x + 3)(x + 4) = 5
x^2 + 3x + 4x + 12 = 5
x^2 + 7x + 7 = 0
Confirmed by sujaysen [4/30/2015 1:50:55 PM]
The line of symmetry of the parabola whose equation is y = ax^2 - 4x + 3 is x = -2. -1 is the value of "a".
4/2a = -2
4 = -4a
a = -1
3 units right is the translation of the graph of y = x^2 that results in the graph of y = (x - 3)^2.
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