What is the length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12?

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The length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12 is sqrt (5^2 + 12^2) = 13

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Asked 4/28/2015 11:47:56 AM

Updated 4/29/2015 9:05:10 PM

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yeswey

The length of the hypotenuse of a right triangle whose legs have lengths of 5 and 12 is sqrt (5^2 + 12^2) = 13

Added 4/29/2015 9:05:10 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [5/5/2015 10:04:10 AM]

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3x+1 =7

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Updated 4/24/2015 11:18:07 AM

2 Answers/Comments

yeswey

3x+1 =7
3x=7-1=6
x=6/3=2

Added 4/24/2015 11:18:02 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [4/30/2015 1:48:20 PM]

jeifunk

3x+1 =7
3x = 7 - 1
3x = 6
x = 6/3
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Added 4/24/2015 11:18:07 AM

This answer has been confirmed as correct and helpful.

2x 2 - 2x - 1 = 0

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Updated 5/4/2015 10:08:20 PM

3 Answers/Comments

yeswey

2x^2 - 2x - 1 = 0
a = 2, b = -2, c = -1
b^2 - 4ac = (-2)^2 - 4(2)(-1) = 4 + 8 = 12
x = [-b ± sqrt (b^2 - 4ac)]/2a
= (2 ± sqrt 12)/4
= (2 ± 2 sqrt 3)/4
= (1 ± sqrt 3)/2

Added 5/4/2015 10:06:24 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [5/5/2015 9:59:11 AM]

yeswey

x^2 + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 or x = -4

Added 5/4/2015 10:07:03 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [5/5/2015 9:59:38 AM]

yeswey

5x^2 + 7x = 6
5x^2 + 7x - 6 = 0
(x + 2)(5x - 3) = 0
x = -2 or x = 3/5

Added 5/4/2015 10:07:57 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [5/5/2015 10:00:11 AM]

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Updated 5/4/2015 8:30:18 AM

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yeswey

y = (x - 3)^2 is of a parabola with a vertex at (3, 0).

Added 5/4/2015 8:28:28 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [5/5/2015 10:04:59 AM]

yeswey

A parabola whose equation is y = (x - 5)^2 - 2 has a vertex at (5, -2)

Added 5/4/2015 8:29:12 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [5/5/2015 10:07:52 AM]

yeswey

y = x^2 + 3 is of a parabola with a vertex at (0, 3).

Added 5/4/2015 8:30:18 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [5/5/2015 10:08:17 AM]

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yeswey

A parabola opens down if the value of "a" is negative in the general form of the equation.

Added 4/29/2015 9:53:17 PM

This answer has been confirmed as correct and helpful.

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yeswey

The vertex of the parabola whose equation is y = x^2 + 6x + 2 is (-3, -7).

Added 4/29/2015 9:55:17 PM

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Confirmed by Andrew. [4/30/2015 2:56:23 AM]

yeswey

The vertex of the parabola whose equation is y = -x^2 - 4x - 3 is (-2, 1).

Added 4/29/2015 9:56:42 PM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [4/30/2015 2:56:42 AM]

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Question

Not Answered

Updated 4/29/2015 8:49:57 PM

3 Answers/Comments

janezeshun

(x + 3)(x + 4) = 5 is quadratic.
(x + 3)(x + 4) = 5
x^2 + 3x + 4x + 12 = 5
x^2 + 7x + 7 = 0

Added 4/29/2015 8:47:58 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [4/30/2015 1:50:55 PM]

janezeshun

The line of symmetry of the parabola whose equation is y = ax^2 - 4x + 3 is x = -2. -1 is the value of "a".
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Added 4/29/2015 8:49:02 PM