Solve by substitution method. 15x - 20y = 1; 5y = 2 + 15x

15x - 20y = 1; 5y = 2 + 15x ; (5y = 2 + 15x)/(5) ; y = 2/5 + 3x ; 15x - 20(2/5 + 3x) = 1 ; 15x - 8 - 60x = 1 ; -45x - 8 = 1 ; -45x = 1 + 8 ; -45x = 9 ; x = 9/-45 ; x = -1/5 ; 15(-1/5) - 20y = 1 ; -3 - 20y = 1 ; -20y = 1 + 3 ; -20y = 4 ; y = 4/-20 ; y = -1/5 ; Solution set: (-1/5, -1/5)

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Asked 8/15/2013 11:00:48 PM

Updated 46 days ago|6/2/2018 11:21:18 AM

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Edited by Masamune [6/2/2018 11:21:15 AM]

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15x - 20y = 1;

5y = 2 + 15x ;

(5y = 2 + 15x)/(5) ;

y = 2/5 + 3x ;

15x - 20(2/5 + 3x) = 1 ;

15x - 8 - 60x = 1 ;

-45x - 8 = 1 ;

-45x = 1 + 8 ;

-45x = 9 ;

x = 9/-45 ;

x = -1/5 ;

15(-1/5) - 20y = 1 ;

-3 - 20y = 1 ;

-20y = 1 + 3 ;

-20y = 4 ;

y = 4/-20 ;

y = -1/5 ;

Solution set: (-1/5, -1/5)

5y = 2 + 15x ;

(5y = 2 + 15x)/(5) ;

y = 2/5 + 3x ;

15x - 20(2/5 + 3x) = 1 ;

15x - 8 - 60x = 1 ;

-45x - 8 = 1 ;

-45x = 1 + 8 ;

-45x = 9 ;

x = 9/-45 ;

x = -1/5 ;

15(-1/5) - 20y = 1 ;

-3 - 20y = 1 ;

-20y = 1 + 3 ;

-20y = 4 ;

y = 4/-20 ;

y = -1/5 ;

Solution set: (-1/5, -1/5)

Added 46 days ago|6/2/2018 11:21:18 AM

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