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what is 30 kg times 20 m/s^2?
Force=ma=30*20 m/s^2=600N.
Expert answered|Cheruiyot|Points 7885|
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Asked 2/27/2023 10:54:07 AM
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A 7.5 kg block is placed on a table. If its bottom surface area is 0.6 m , how much pressure does the block exert on the tabletop?
Weegy: A 7.5 kg block is placed on a table. If its bottom surface area is 0.6 m2, 122.5 Pa does the block exert on the tabletop. P = F/A where F = mg F = 7.5 ( 9.81) = 73.6 N P = 73.6 N / 0.6 m^2 = 122.5 Pa User: A 7.5 kg block is placed on a table. If its bottom surface area is 0.6 m^2, how much pressure does the block exert on the tabletop? Weegy: A 7.5 kg block is placed on a table. If its bottom surface area is 0.6 m2, 122.5 Pa does the block exert on the tabletop. Solution: P = F / A where F = mg P = mg / A P = (7.5 x 9.8) / 0.6 P = 122.5 Pa (More)
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