Solve the system algebraically. 3x - 2y - 1 = 0 y = 5x + 4 What is the solution? {(-9/7,-17/7)} {(9/7,17/7)} {(9/7,-17/7)}
3x - 2y - 1 = 0 y = 5x + 4 substitute y in the first equation we get: 3x - 2(5x + 4) - 1 = 0 3x - 10x - 8 - 1 = 0 -7x = 9 x = -9/7 y = 5(-9/7) + 4 = -45/7 + 28/7 = -17/7 The solution for the system 3x - 2y - 1 = 0 y = 5x + 4 is (-9/7, -17/7)
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Updated 5/4/2015 9:41:01 AM
Confirmed by Andrew. [5/4/2015 9:41:01 AM]
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The Absolute Value is sometimes negative. True or false
Updated 5/18/2015 10:34:21 PM
The Absolute Value is sometimes negative. FALSE.
Confirmed by jeifunk [5/18/2015 10:34:12 PM]
Solve the system algebraically. 4x - 5y = 3 x = 3 - y What is the value of x? 9/7 24/14 33/14
Weegy: 4x - 5y = 3, x = 3 - y; (x + y = 3) * (-4); -4x - 4y = -12; ( 4x - 5y = 3) + (-4x - 4y = -12); -9y = -9; y = -9/-9 = 1; 4x - 5(1) = 3; 4x - 5 = 3; 4x = 3 + 5; 4x = 8; x = 8/4 = 2; The solution set of the systems 4x - 5y = 3 x = 3 - y is {2, 1}. The value of x is 2. (More)
Updated 5/4/2015 9:40:15 AM
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