Given the following sequence, find the 15th term: 3, 1, –1, –3, –5, . . .
A. –28
B. –25
C. –33
D. –21

Question

Asked 11/13/2014 6:29:54 AM

Updated 11/15/2014 9:02:33 PM

2 Answers/Comments

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kellymi729|Points 103|

Question

Asked 11/13/2014 6:29:54 AM

Updated 11/15/2014 9:02:33 PM

2 Answers/Comments

Rating

5

Given the following sequence, find the 50th term: 1.3, 1.5, 1.7, 1.9, 2.1, is 11.1 .

Common difference = 2.1 - 1.9 = 0.2

50th term = 1.3 + (50 - 1)*0.2= 1.3 + 9.8 = 11.1 .

Common difference = 2.1 - 1.9 = 0.2

50th term = 1.3 + (50 - 1)*0.2= 1.3 + 9.8 = 11.1 .

Added 11/15/2014 9:02:33 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [11/20/2014 9:13:11 AM]

what is accurate regarding both west africa and latin america before 1500 **Weegy:** Polytheism was important in both areas is accurate regarding both west Africa and Latin America before 1500. (More)

Question

Expert Answered

Asked 11/6/2014 5:47:54 AM

0 Answers/Comments

The slope of every horizontal line is…
A. 0
B. 1
C. 1/2
D. undefined **Weegy:** The slope of every horizontal line is 0. **User:** What is the slope of the line that contains the points (4, –4) and (7, –6)?
A. 3/2
B. -2/3
C. -3/2
D. 2 (More)

Question

Updated 11/18/2014 8:50:18 AM

1 Answer/Comment

The value of y varies directly with x, and y = 3 when x = 1.
Find y when x = 5.
A. 12
B. 15
C. 2
D. 15 User: The value of y varies directly with x, and y = 4 when x = 1.
Find y when x = 3.
A. 12
B. 7
C. 1
D. 7 User: The value of y varies directly with x, and y = 4 when x = 1.
Find y when x = 3.
A. 12
B. 7
C. 1
D. 7
User: The value of y varies directly with x, and y = 1 when x = 2.
Find y when x = 4.
A. 2
B. 4
C. 2
D. 8 User: The value of y varies directly with ...**Weegy:** An example of a quadratic equation is y = x^2 - 5 **User:** The value of y varies directly with x, and y = 4 when x = 10.
Find y when x = 1.
A. 2.5
B. 2.5
C. 0.4
D. 0.4 **User:** The value of y varies directly with x, and y = 4 when x = 10.
Find y when x = 1.
A. 2.5
B. 2.5
C. 0.4
D. 0.4 **User:** The value of y varies directly with x, and y = 12 when x = 6.
Find y when x = 4.
A. 8
B. 8
C. 6
D. 6 **User:**
The value of y varies directly with x, and y = 3 when x = 6.
Find y when x = 1.
A. 0.5
B. 0.5
C. 2
D. 2 **User:**
The value of y varies directly with x, and y = 3 when x = 6.
Find y when x = 1.
A. 0.5
B. 0.5
C. 2
D. 2 **User:** The value of y varies directly with x, and y = 1 when x = 2.
Find y when x = 4.
A. 2
B. 4
C. 2
D. 8 **User:**
Which equation below is a direct variation?
A. 0.05x = y
B. x + 2 = y
C. y+2/3=x
D. y = 2x + 6 **Weegy:** The equation 0.05x=y is a direct variation. **User:** The value of y varies directly with x, and y = 12 when x = 6.
Find y when x = 4.
A. 8
B. 8
C. 24
D. 24 **User:** The value of y varies directly with x, and y = 12 when x = 6.
Find y when x = 4.
A. 8
B. 8
C. 24
D. 24 **User:**
Which equation below is a direct variation?
A. 1/6x=y
B. x + 2 = y
C. y + 2 = x
D. y = 2x + 6
**Weegy:** An example of a quadratic equation is y = x^2 - 5 **User:**
The value of y varies directly with x, and y = 4 when x = 10.
Find y when x = 1.
A. 2.5
B. 2.5
C. 0.4
D. 0.4 **User:** The value of y varies directly with x, and y = 12 when x = 6.
Find y when x = 4.
A. 8
B. 8
C. 6
D. 6 **User:** The value of y varies directly with x, and y = 1 when x = 3.
Find y when x = 18.
A. 9
B. 3
C. 6
D. 2
**User:**
The value of y varies directly with x, and y = 3 when x = 1.
Find y when x = 5.
A. 12
B. 15
C. 2
D. 15 **User:** The value of y varies directly with x, and y = 3 when x = 6.
Find y when x = 1.
A. 0.5
B. 0.5
C. 2
D. 2 **User:**
Which equation below is a direct variation?
A. 0.05x ... (More)

Question

Updated 11/20/2014 2:17:17 AM

6 Answers/Comments

The value of y varies directly with x, and y = 4 when x = 1.

The equation is y = kx where k is the constant.

With given value we get k = y/x = 4/1 = 4

The equation is y = 4x

when x = 3, y = 4(3) = 12

The equation is y = kx where k is the constant.

With given value we get k = y/x = 4/1 = 4

The equation is y = 4x

when x = 3, y = 4(3) = 12

Added 11/20/2014 2:07:38 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/20/2014 10:01:49 AM]

The value of y varies directly with x, and y = 12 when x = 6.

The equation is y = kx where k is the constant.

With given values we get k = y/x = 12/6 = 2

The equation is y = 2x

when x = 4, y = 2(4) = 8

The equation is y = kx where k is the constant.

With given values we get k = y/x = 12/6 = 2

The equation is y = 2x

when x = 4, y = 2(4) = 8

Added 11/20/2014 2:10:19 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/20/2014 10:03:06 AM]

1/6x=y is a direct variation.

Added 11/20/2014 2:11:39 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/20/2014 10:04:10 AM]

The value of y varies directly with x, and y = 4 when x = 10.

The equation is y = kx where k is the constant

With given values of x and y we get k = y/x = 4/10 = 0.4

The equation is y = 0.4x

when x = 1, y = 0.4(1) = 0.4

The equation is y = kx where k is the constant

With given values of x and y we get k = y/x = 4/10 = 0.4

The equation is y = 0.4x

when x = 1, y = 0.4(1) = 0.4

Added 11/20/2014 2:14:53 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/20/2014 10:05:03 AM]

The value of y varies directly with x, and y = 3 when x = 6.

The equation is y = kx where k is the constant. k = y/x = 3/6 = 0.5

The equation is y = 0.5x

when x = 1, y = 0.5(1) = 0.5

The equation is y = kx where k is the constant. k = y/x = 3/6 = 0.5

The equation is y = 0.5x

when x = 1, y = 0.5(1) = 0.5

Added 11/20/2014 2:17:17 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/20/2014 10:05:38 AM]

Given the following sequence, find the 26th term: 0, 1, 2, 3, 4, . . .
A. 24
B. 25
C. 26
D. 27 **Weegy:** The 26 term is 25. an = 0 + (26 - 1)1 =0+(26-1) =0+25 =25 **User:**
Given the following sequence, find the 23rd term:
10.5, 11, 11.5, 12, 12.5, . . .
A. 20.5
B. 21
C. 21.5
D. 22 **Weegy:** The answer is B. 21 **User:** Given the following sequence, find the 50th term:
1.2, 1.4, 1.6, 1.8, 2, . . .
A. 9.8
B. 11
C. 10.8
D. 10.2 (More)

Question

Updated 11/16/2014 10:48:46 PM

4 Answers/Comments

Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . .is 21.5 .

Common difference = 12.5 - 12 = 0.5

23rd term = 10.5 + (23 - 1)*0.5 = 10.5 + 22*0.5 = 10.5 + 11 = 21.5

Common difference = 12.5 - 12 = 0.5

23rd term = 10.5 + (23 - 1)*0.5 = 10.5 + 22*0.5 = 10.5 + 11 = 21.5

Added 11/16/2014 10:48:31 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/17/2014 12:07:19 AM]

Given the following sequence, find the 50th term: 1.2, 1.4, 1.6, 1.8, 2, . . is 11 .

common difference = 2 - 1.8 = 0.2

50th term = 1.2 + (50 - 1)*0.2 = 1.2 + 49*0.2 = 1.2 + 9.8 = 11 .

common difference = 2 - 1.8 = 0.2

50th term = 1.2 + (50 - 1)*0.2 = 1.2 + 49*0.2 = 1.2 + 9.8 = 11 .

Added 11/16/2014 10:48:46 PM

Given the following sequence, find the 26th term: 0, 1, 2, 3, 4, . . .
A. 24
B. 25
C. 26
D. 27 **Weegy:** The 26 term is 25. an = 0 + (26 - 1)1 =0+(26-1) =0+25 =25 **User:** Given the following sequence, find the 22nd term: 3, 5, 7, 9, 11, . . .
A. 50
B. 47
C. 45
D. 46
**Weegy:** B. 47 **User:**
Given the following sequence, find the 25th term: 0, 1, 2, 3, 4, . . .
A. 24
B. 25
C. 26
D. 27 **Weegy:** Given the following sequence, find the 25th term: 0, 1, 2, 3, 4, . . . The answer is A. 24 **User:**
Given the following sequence, find the 14th term: 3, 1, –1, –3, –5, . . .
A. –28
B. –25
C. –23
D. –21 **Weegy:** The answer is C. -23 **User:** Given the following sequence, find the 23rd term:
10.5, 11, 11.5, 12, 12.5, . . .
A. 20.5
B. 21
C. 21.5
D. 22 **Weegy:** The answer is B. 21 **User:**
Given the following sequence, find the 23rd term: 3, 5, 7, 9, 11, . . .
A. 50
B. 47
C. 25
D. 26 **Weegy:** The answer is B. 47. **User:** Given the following sequence, find the 50th term:
1.2, 1.4, 1.6, 1.8, 2, . . .
A. 9.8
B. 11
C. 10.8
D. 10.2 (More)

Question

Updated 11/15/2014 4:30:48 AM

2 Answers/Comments

Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . .is 21.5 .

Common difference = 12.5 - 12 = 0.5

23rd term = 10.5 + (23 - 1)*0.5 = 10.5 + 22*0.5 = 10.5 + 11 = 21.5 .

Common difference = 12.5 - 12 = 0.5

23rd term = 10.5 + (23 - 1)*0.5 = 10.5 + 22*0.5 = 10.5 + 11 = 21.5 .

Added 11/15/2014 4:29:05 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [11/15/2014 12:49:37 PM]

Given the following sequence, find the 50th term: 1.2, 1.4, 1.6, 1.8, 2, . . is 11 .

common difference = 2 - 1.8 = 0.2

50th term = 1.2 + (50 - 1)*0.2 = 1.2 + 49*0.2 = 1.2 + 9.8 = 11 .

common difference = 2 - 1.8 = 0.2

50th term = 1.2 + (50 - 1)*0.2 = 1.2 + 49*0.2 = 1.2 + 9.8 = 11 .

Added 11/15/2014 4:30:48 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [11/15/2014 12:50:29 PM]

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