Given the following sequence, find the 15th term: 3, 1, –1, –3, –5, . . . A. –28 B. –25 C. –33 D. –21
Question
Updated 11/15/2014 9:02:33 PM
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Original conversation
User: Given the following sequence, find the 15th term: 3, 1, –1, –3, –5, . . . A. –28 B. –25 C. –33 D. –21

Weegy: B -25
kellymi729|Points 103|

User: Given the following sequence, find the 50th term: 1.3, 1.5, 1.7, 1.9, 2.1, . . . A. 10.9 B. 11.1 C. 9.8 D. 8.9

Question
Updated 11/15/2014 9:02:33 PM
Rating
5
Given the following sequence, find the 50th term: 1.3, 1.5, 1.7, 1.9, 2.1, is 11.1 .
Common difference = 2.1 - 1.9 = 0.2
50th term = 1.3 + (50 - 1)*0.2= 1.3 + 9.8 = 11.1 .
Confirmed by sujaysen [11/20/2014 9:13:11 AM]

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The slope of every horizontal line is… A. 0 B. 1 C. 1/2 D. undefined
Weegy: The slope of every horizontal line is 0. User: What is the slope of the line that contains the points (4, –4) and (7, –6)? A. 3/2 B. -2/3 C. -3/2 D. 2 (More)
Question
Updated 11/18/2014 8:50:18 AM
The slope of the line that contains the points (4, –4) and (7, –6) is -2/3.
Slope = [-6 - (-4)]/(7 - 4) = -2/3
Confirmed by jeifunk [11/18/2014 8:51:18 AM]
The value of y varies directly with x, and y = 3 when x = 1. Find y when x = 5. A. 12 B. 15 C. 2 D. 15 User: The value of y varies directly with x, and y = 4 when x = 1. Find y when x = 3. A. 12 B. 7 C. 1 D. 7 User: The value of y varies directly with x, and y = 4 when x = 1. Find y when x = 3. A. 12 B. 7 C. 1 D. 7 User: The value of y varies directly with x, and y = 1 when x = 2. Find y when x = 4. A. 2 B. 4 C. 2 D. 8 User: The value of y varies directly with ...
Weegy: An example of a quadratic equation is y = x^2 - 5 User: The value of y varies directly with x, and y = 4 when x = 10. Find y when x = 1. A. 2.5 B. 2.5 C. 0.4 D. 0.4 User: The value of y varies directly with x, and y = 4 when x = 10. Find y when x = 1. A. 2.5 B. 2.5 C. 0.4 D. 0.4 User: The value of y varies directly with x, and y = 12 when x = 6. Find y when x = 4. A. 8 B. 8 C. 6 D. 6 User: The value of y varies directly with x, and y = 3 when x = 6. Find y when x = 1. A. 0.5 B. 0.5 C. 2 D. 2 User: The value of y varies directly with x, and y = 3 when x = 6. Find y when x = 1. A. 0.5 B. 0.5 C. 2 D. 2 User: The value of y varies directly with x, and y = 1 when x = 2. Find y when x = 4. A. 2 B. 4 C. 2 D. 8 User: Which equation below is a direct variation? A. 0.05x = y B. x + 2 = y C. y+2/3=x D. y = 2x + 6 Weegy: The equation 0.05x=y is a direct variation. User: The value of y varies directly with x, and y = 12 when x = 6. Find y when x = 4. A. 8 B. 8 C. 24 D. 24 User: The value of y varies directly with x, and y = 12 when x = 6. Find y when x = 4. A. 8 B. 8 C. 24 D. 24 User: Which equation below is a direct variation? A. 1/6x=y B. x + 2 = y C. y + 2 = x D. y = 2x + 6 Weegy: An example of a quadratic equation is y = x^2 - 5 User: The value of y varies directly with x, and y = 4 when x = 10. Find y when x = 1. A. 2.5 B. 2.5 C. 0.4 D. 0.4 User: The value of y varies directly with x, and y = 12 when x = 6. Find y when x = 4. A. 8 B. 8 C. 6 D. 6 User: The value of y varies directly with x, and y = 1 when x = 3. Find y when x = 18. A. 9 B. 3 C. 6 D. 2 User: The value of y varies directly with x, and y = 3 when x = 1. Find y when x = 5. A. 12 B. 15 C. 2 D. 15 User: The value of y varies directly with x, and y = 3 when x = 6. Find y when x = 1. A. 0.5 B. 0.5 C. 2 D. 2 User: Which equation below is a direct variation? A. 0.05x ... (More)
Question
Updated 11/20/2014 2:17:17 AM
The value of y varies directly with x, and y = 4 when x = 1.
The equation is y = kx where k is the constant.
With given value we get k = y/x = 4/1 = 4
The equation is y = 4x
when x = 3, y = 4(3) = 12
Confirmed by andrewpallarca [11/20/2014 10:01:49 AM]
The value of y varies directly with x, and y = 12 when x = 6.
The equation is y = kx where k is the constant.
With given values we get k = y/x = 12/6 = 2
The equation is y = 2x
when x = 4, y = 2(4) = 8
Confirmed by andrewpallarca [11/20/2014 10:03:06 AM]
1/6x=y is a direct variation.
Confirmed by andrewpallarca [11/20/2014 10:04:10 AM]
The value of y varies directly with x, and y = 4 when x = 10.
The equation is y = kx where k is the constant
With given values of x and y we get k = y/x = 4/10 = 0.4
The equation is y = 0.4x
when x = 1, y = 0.4(1) = 0.4
Confirmed by andrewpallarca [11/20/2014 10:05:03 AM]
The value of y varies directly with x, and y = 3 when x = 6.
The equation is y = kx where k is the constant. k = y/x = 3/6 = 0.5
The equation is y = 0.5x
when x = 1, y = 0.5(1) = 0.5
Confirmed by andrewpallarca [11/20/2014 10:05:38 AM]
Given the following sequence, find the 26th term: 0, 1, 2, 3, 4, . . . A. 24 B. 25 C. 26 D. 27
Weegy: The 26 term is 25. an = 0 + (26 - 1)1 =0+(26-1) =0+25 =25 User: Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . . A. 20.5 B. 21 C. 21.5 D. 22 Weegy: The answer is B. 21 User: Given the following sequence, find the 50th term: 1.2, 1.4, 1.6, 1.8, 2, . . . A. 9.8 B. 11 C. 10.8 D. 10.2 (More)
Question
Updated 11/16/2014 10:48:46 PM
Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . .is 21.5 .
Common difference = 12.5 - 12 = 0.5
23rd term = 10.5 + (23 - 1)*0.5 = 10.5 + 22*0.5 = 10.5 + 11 = 21.5
Confirmed by jeifunk [11/17/2014 12:07:19 AM]
Given the following sequence, find the 50th term: 1.2, 1.4, 1.6, 1.8, 2, . . is 11 .
common difference = 2 - 1.8 = 0.2
50th term = 1.2 + (50 - 1)*0.2 = 1.2 + 49*0.2 = 1.2 + 9.8 = 11 .
Given the following sequence, find the 26th term: 0, 1, 2, 3, 4, . . . A. 24 B. 25 C. 26 D. 27
Weegy: The 26 term is 25. an = 0 + (26 - 1)1 =0+(26-1) =0+25 =25 User: Given the following sequence, find the 22nd term: 3, 5, 7, 9, 11, . . . A. 50 B. 47 C. 45 D. 46 Weegy: B. 47 User: Given the following sequence, find the 25th term: 0, 1, 2, 3, 4, . . . A. 24 B. 25 C. 26 D. 27 Weegy: Given the following sequence, find the 25th term: 0, 1, 2, 3, 4, . . . The answer is A. 24 User: Given the following sequence, find the 14th term: 3, 1, –1, –3, –5, . . . A. –28 B. –25 C. –23 D. –21 Weegy: The answer is C. -23 User: Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . . A. 20.5 B. 21 C. 21.5 D. 22 Weegy: The answer is B. 21 User: Given the following sequence, find the 23rd term: 3, 5, 7, 9, 11, . . . A. 50 B. 47 C. 25 D. 26 Weegy: The answer is B. 47. User: Given the following sequence, find the 50th term: 1.2, 1.4, 1.6, 1.8, 2, . . . A. 9.8 B. 11 C. 10.8 D. 10.2 (More)
Question
Updated 11/15/2014 4:30:48 AM
Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . .is 21.5 .
Common difference = 12.5 - 12 = 0.5
23rd term = 10.5 + (23 - 1)*0.5 = 10.5 + 22*0.5 = 10.5 + 11 = 21.5 .
Confirmed by sujaysen [11/15/2014 12:49:37 PM]
Given the following sequence, find the 50th term: 1.2, 1.4, 1.6, 1.8, 2, . . is 11 .
common difference = 2 - 1.8 = 0.2
50th term = 1.2 + (50 - 1)*0.2 = 1.2 + 49*0.2 = 1.2 + 9.8 = 11 .
Confirmed by sujaysen [11/15/2014 12:50:29 PM]
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