Question and answer
5/2a*3/a
Question
Asked 4/8/2014 10:10:02 AM
Updated 4/8/2014 10:05:23 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [4/8/2014 11:33:30 AM], Followed by yeswey, Unfollowed by yeswey
s
Original conversation
User: 5/2a*3/a

Weegy: Solution: 2a(a - 5) + 4(a - 5) Now distribute 2a and 4 2a^2 - 10a + 4a - 20 Now combine like terms 2a^2 - 6a - 20 Now you have to factor and this is a different kind of factoring because a^2 has a coefficient of more than one 2a^2 + 4a - 10a - [ 20 Now factor 2a (a + 2) 10 (a + 2) Now make them into two groups (2a - 10) (a + 2) Solve for a Solutions: 5, -2 ]
nicole008|Points 30|

Question
Asked 4/8/2014 10:10:02 AM
Updated 4/8/2014 10:05:23 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [4/8/2014 11:33:30 AM], Followed by yeswey, Unfollowed by yeswey
New answers
Rating
3
5/2a*3/a

= 15/2

Added 4/8/2014 11:33:31 AM
This answer has been confirmed as correct and helpful.
Flagged by yeswey [4/8/2014 10:00:07 PM], Unflagged by yeswey [4/8/2014 10:01:59 PM]
3
5/(2a) * 3/a = (5*3)/(2a*a) = 15/(2a^2)
Added 4/8/2014 10:03:58 PM
This answer has been confirmed as correct and helpful.
Comments
I unflagged your answer since i realized that you did it by taking 5/2a as (5/2)a or 5a/2, didnt you?
Added 4/8/2014 10:03:30 PM
Such questions can mislead us because of incorrect format.
Added 4/8/2014 10:05:23 PM
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Questions asked by the same visitor
Simplify the rational expression. State any excluded values. x^2-x-6/x+2
Question
Updated 4/8/2014 7:24:25 PM
1 Answer/Comment
(x^2 - x - 6)/(x + 2)
= (x - 3)(x + 2)/(x + 2)
= x - 3 where x can not be -2.
Added 4/8/2014 7:24:25 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/8/2014 7:25:06 PM]
Simplify the rational expression. State any excluded values. 2x/-5x+x^2
Weegy: (-5x)2 is -10x. (More)
Question
Updated 4/8/2014 7:07:24 PM
1 Answer/Comment
2x/(-5x+x^2)
= 2x/[x(x - 5)]
= 2/(x - 5) where x can not be 0 or 5.
Added 4/8/2014 7:07:24 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/8/2014 7:10:10 PM]
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